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kap26 [50]
3 years ago
14

Is 14 squared bigger than 3.14

Mathematics
1 answer:
zloy xaker [14]3 years ago
6 0

Answer:

Yes, 14 squared is definitely bigger than 3.14. When you square a number, you multiply it by itself, and even if you didn't do that, 14 would still be a bigger number than 3.14.

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Ayúdenme por favor necesito esto resolvió para mañana
lions [1.4K]

Answer:

Cómo puedo ayudar

Step-by-step explanation:

7 0
3 years ago
Explain the steps in calculating the mean absolute<br>deviation of a set of data.​
Sergeeva-Olga [200]

Answer:

To find the mean absolute deviation of the data, start by finding the mean of the data set. Find the sum of the data values, and divide the sum by the number of data values. ... Divide the sum of the absolute values of the differences by the number of data values.

8 0
3 years ago
Read 2 more answers
Set up the integral that represents the arc length of the curve f(x) = ln(x) + 5 on [1, 3], and then use Simpson's Rule with n =
marta [7]

Answer:

The integral for the arc of length is:

\displaystyle\int_1^3\sqrt{1+\frac{1}{x^2}}dx

By using Simpon’s rule we get: 1.5355453

And using technology we get:  2.3020

The approximation is about 33% smaller than the exact result.

Explanation:

The formula for the length of arc of the function f(x) in the interval [a,b] is:

\displaystyle\int_a^b \sqrt{1+[f'(x)]^2}dx

We need the derivative of the function:

f'(x)=\frac{1}{x}

And we need it squared:

[f'(x)]^2=\frac{1}{x^2}

Then the integral is:

\displaystyle\int_1^3\sqrt{1+\frac{1}{x^2}}dx

Now, the Simposn’s rule with n=4 is:

\displaystyle\int_a^b g(x)}dx\approx\frac{\Delta x}{3}\left( g(a)+4g(a+\Delta x)+2g(a+2\Delta x) +4g(a+3\Delta x)+g(b) \right)

In this problem:

a=1,b=3,n=4, \displaystyle\Delta x=\frac{b-a}{n}=\frac{2}{4}=\frac{1}{2},g(x)= \sqrt{1+\frac{1}{x^2}}

So, the Simposn’s rule formula becomes:

\displaystyle\int_1^3\sqrt{1+\frac{1}{x^2}}dx\\\approx \frac{\frac{1}{3}}{3}\left( \sqrt{1+\frac{1}{1^2}} +4\sqrt{1+\frac{1}{\left(1+\frac{1}{2}\right)^2}} +2\sqrt{1+\frac{1}{\left(1+\frac{2}{2}\right)^2}} +4\sqrt{1+\frac{1}{\left(1+\frac{3}{2}\right)^2}} +\sqrt{1+\frac{1}{3^2}} \right)

Then simplifying a bit:

\displaystyle\int_1^3\sqrt{1+\frac{1}{x^2}}dx \approx \frac{1}{9}\left( \sqrt{1+\frac{1}{1^2}} +4\sqrt{1+\frac{1}{\left(\frac{3}{2}\right)^2}} +2\sqrt{1+\frac{1}{\left(2\right)^2}} +4\sqrt{1+\frac{1}{\left(\frac{5}{2}\right)^2}} +\sqrt{1+\frac{1}{3^2}} \right)

Then we just do those computations and we finally get the approximation via Simposn's rule:

\displaystyle\int_1^3\sqrt{1+\frac{1}{x^2}}dx\approx 1.5355453

While when we do the integral by using technology we get: 2.3020.

The approximation with Simpon’s rule is close but about 33% smaller:

\displaystyle\frac{2.3020-1.5355453}{2.3020}\cdot100\%\approx 33\%

8 0
3 years ago
879 divide by 48 show your work
levacccp [35]

Answer:

18 remainder 15

Step-by-step explanation:

4 0
3 years ago
You want to rent movies online, The new service charges a sign up fee of $10, Then,
gavmur [86]

Answer:

y=12x+10 or f(x)=12x+10

Step-by-step explanation:

If it costs $12 per month to rent as many movies as you want, then that can be represented as 12x

Since $10 is a flat fee and doesn't change, this gets added seperately to 12x

Thus, the final equation is y=12x+10 or f(x)=12x+10

Hope this helped!

3 0
3 years ago
Read 2 more answers
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