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Ad libitum [116K]
3 years ago
5

QuizNo Copy paste_-1. Write down the benefits of potatoes !! (as many as 5)​

Biology
1 answer:
kati45 [8]3 years ago
6 0

Answer:

fiber, antioxidants, vitiman c

Explanation:

so fiber for digestvie health

antioxidants for disease provention

not sure  if thats  the answer ur looking for  

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The pictures show close-up views of a fir tree and a cactus.
Akimi4 [234]

The fir tree can be found in the coniferous forest biome, and the cactus can be found in the desert biome.

Option C.

<h3><u>Explanation:</u></h3>

Both the cactus and fir trees are having modified tree leaves due to the same purpose - saving water.

The fir trees are found in the coniferous forests which are mainly seen in mountains or in the temperate region. Both the regions face very cold climates and frequent snowfalls in every years. This is why there's a lack of water in the surroundings. This is why they need to save water and minimize transpiration.

Whereas the cacti are found in desert or semi arid regions where water is itself very scarce and temperature is either very high or very low. So they have their leaves converted into spines which help to reduce transpiration.

8 0
3 years ago
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Explain how DNA AND RNA WORK
lutik1710 [3]

Answer:

Explanation:

DNA are molecules that store genetic information in all organisms.

RNA are molecules that will form proteins based on the instructions coming from DNA.

5 0
3 years ago
1. Which of these describes a chemical
valentina_108 [34]

The answer is c in my opinion
6 0
4 years ago
A company is researching mining at four different land areas using different types of equipment. The table below shows the costs
Tasya [4]

Answer: i think it might be c

Explanation:

4 0
4 years ago
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please show work Nerodia sipedon insularum is a species of the Northern Water Snake that lives on islands in the western part of
raketka [301]

Answer:

Explanation:

From the question, the total population = 171 i.e (80+71+21)

Genetic frequency therefore; BB = 71/171 = 0.42

Bb = 80/171 = 0.47

bb = 20/171 = 0.12

Allele frequency therefore;

Allele B = 0.42+(0.50×0.47) = 0.66

Allele b = (0.50×0.47)+0.12 = 0.36

Note all values were rounded up to two significant figures

5 0
3 years ago
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