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2 years ago

Will give brainliest!

Mathematics

1 answer:

yuradex [85]2 years ago

7 0

Answer:

$f^{-1}(x) = x/2 +2$

Step-by-step explanation:

let $f^{-1} (x)$ = y

then f(y) = x

2y-4 =x

2y =x+4

y= x/2 +2

hence f^{-1} (x) = x/2 +2

You might be interested in

A circle is inscribed in a square is 10 inch sides what is the circumference of the circle use 3.14 as an approximation for pie

MissTica

Answer:

31.4 inches

Step-by-step explanation:

If a circle is inscribed in a square then diameter of circle inscribed is same as side as of square.

In the given problem it is given that side of square is 10 inches.

So diameter of circle inscribed is 10 inches

we know radius of circle is half of diameter of circle

Thus, radius of circle inscribed = diameter of circle/2 = 10/2 = 5inches.

Expression to calculate circumference of circle is given by $2\pi r$

where r is the radius of circle.

Thus circumference of circle inscribed is

$2*\pi *5\\=> 10*3.14 \\=> 31.4$

Thus, circumference of circle inscribed is 31.4 inches

6 0

2 years ago

A limo driver needs to make more than $450 in one day. He charges a rental fee of $375 and $0.85 per mile. What inequality repre

spin [16.1K]

Answer:

Step-by-step explanation:

0.85x + 375 > 450

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2 years ago

Drag each shape to the correct category. Identify which shapes are similar to shape A and which are not.

Artyom0805 [142]

I need to see the photo

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2 years ago

Help I cannot figure this question out.

netineya [11]

Answer:

B. x = -1 ± i

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

Multiplication Property of Equality
Division Property of Equality
Addition Property of Equality
Subtraction Property of Equality

Algebra I

Standard Form: ax² + bx + c = 0
Factoring
Quadratic Formula: $\displaystyle x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}$

Algebra II

Imaginary Numbers: √-1 = i

Step-by-step explanation:

Step 1: Define

x² + 2x = -2

Step 2: Identify Variables

Rewrite Quadratic in Standard Form [Addition Property of Equality]: x² + 2x + 2 = 0
Break up Quadratic: a = 1, b = 2, c = 2

Step 3: Solve for x

Substitute in variables [Quadratic Formula]: $\displaystyle x=\frac{-2 \pm \sqrt{2^2-4(1)(2)}}{2(1)}$
[√Radical] Evaluate exponents: $\displaystyle x=\frac{-2 \pm \sqrt{4-4(1)(2)}}{2(1)}$
Multiply: $\displaystyle x=\frac{-2 \pm \sqrt{4-8}}{2}$
[√Radical] Subtract: $\displaystyle x=\frac{-2 \pm \sqrt{-4}}{2}$
[√Radical] Factor: $\displaystyle x=\frac{-2 \pm \sqrt{-1}\sqrt{4}}{2}$
[√Radicals] Simplify: $\displaystyle x=\frac{-2 \pm 2i}{2}$
Factor: $\displaystyle x=\frac{2(-1 \pm i)}{2}$
Divide: $\displaystyle x = -1 \pm i$