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viva [34]
3 years ago
14

Will give brainliest!

Mathematics
1 answer:
yuradex [85]3 years ago
7 0

Answer:

f^{-1}(x) = x/2 +2

Step-by-step explanation:

let f^{-1} (x) = y

then f(y) = x

2y-4 =x

2y =x+4

y= x/2 +2

hence f^{-1} (x) = x/2 +2

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What is the actual distance between Saugerties and Kingston? Scale: 1 in= 2.5 mi. They are 4 in apart. What is the distance in m
Romashka-Z-Leto [24]

Answer:

that would be 10 miles

Step-by-step explanation:

1 = 2.5 MILES

4:x

2.5 x 4 = 10

if i am wrong please explain cause it might me being dumb or something else

7 0
3 years ago
The average human gestation period is 270 days with a standard deviation of 9 days. The period is normally distributed. What is
Anna35 [415]

Answer:

Probability that a randomly selected woman's gestation period will be between 261 and 279 days is 0.68.

Step-by-step explanation:

We are given that the average human gestation period is 270 days with a standard deviation of 9 days. The period is normally distributed.

Firstly, Let X = women's gestation period

The z score probability distribution for is given by;

         Z = \frac{ X - \mu}{\sigma} ~ N(0,1)

where, \mu = average gestation period = 270 days

            \sigma = standard deviation = 9 days

Probability that a randomly selected woman's gestation period will be between 261 and 279 days is given by = P(261 < X < 279) = P(X < 279) - P(X \leq 261)

         P(X < 279) = P( \frac{ X - \mu}{\sigma} < \frac{279-270}{9} ) = P(Z < 1) = 0.84134

         P(X \leq 261) = P( \frac{ X - \mu}{\sigma} \leq \frac{261-270}{9} ) = P(Z \leq -1) = 1 - P(Z < 1)

                                                           = 1 - 0.84134 = 0.15866

<em>Therefore, P(261 < X < 279) = 0.84134 - 0.15866 = 0.68</em>

Hence, probability that a randomly selected woman's gestation period will be between 261 and 279 days is 0.68.

3 0
3 years ago
WILL MARK BRAINLIEST!! Im on edge 2020!
zhannawk [14.2K]

Answer: 80% of x = 20

Hope this helps bye

Have a lovely day.

7 0
3 years ago
Read 2 more answers
Aidan has 20 ft of fence with which to build a rectangular dog run. What is the maximum area he can enclose? Enter your answer i
irina1246 [14]
<h2>Maximum area is 25 m²</h2>

Explanation:

Let L be the length and W be the width.

Aidan has 20 ft of fence with which to build a rectangular dog run.

         Fencing = 2L + 2W  = 20 ft

                     L + W = 10

                      W = 10 - L

We need to find what is the largest area that can be enclosed.

     Area = Length x Width

      A = LW

       A = L x (10-L) = 10 L - L²

For maximum area differential is zero

So we have

      dA = 0

      10 - 2 L = 0

        L = 5 m

      W = 10 - 5 = 5 m

Area = 5 x 5 = 25 m²

Maximum area is 25 m²

7 0
3 years ago
Which of the following are valid names for the given triangle? Check all that apply.
vfiekz [6]
When naming triangles we name them by the letters on each corner so only answers with T, A, and X in them are correct, so TAX, XTA, and AXT
6 0
3 years ago
Read 2 more answers
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