686 barrels left. If I'm not mistaken this should just be simple subtraction
Answer:
If the reindeer do not fight, there are 5!=120 ways to line them up in a straight line.
Out of these, Bloopin and Rudy are together in 4!=24 times. Similarly Rudy and Bloopin will be together 4!=24 times. So the number of ways they are not together is 120-24-24=72 ways.
Hope this helps. :)
Step-by-step explanation:
Spanish:
Si los renos no luchan, hay 5! = 120 formas de alinearlos en línea recta.
De estos, Bloopin y Rudy están juntos en 4! = 24 veces. De manera similar, Rudy y Bloopin estarán juntos 4! = 24 veces. Entonces, el número de formas en que no están juntas es 120-24-24 = 72 formas.
Espero que esto ayude :)
Answer:
17p
Step-by-step explanation:
Since you don't know how much Sanjay picked you can only explain as a variable. So just put 17 next to p which is 17*p
Divide both sides by 5^2 (which is 25). So p = (5^12)/25. I can't be bothered to plug in into a calculator but be my guest.
