Everything in presence is moving. That is the most essential naturally visible thing to think about the universe. In this way, consider a youthful star and any sensible measure of material about it. Regardless of the possibility that it was by one means or another equally, arbitrarily separated in a circle about the youthful star and moving in any case, the star and its gravitational impacts will rule. So its immense mass turns in a given plane and its gravity field twists fundamentally spacetime in that plane and less so in whatever another plane. In any case, the development of the star drags the only things that are important around it step by step into its rotational plane.
By angular speed, the frequency is 2.39 Hz.
We need to know about the angular speed of harmonic oscillation. the angular speed can be determined as
ω² = k / m
where ω is angular speed, k is spring constant, and m is the mass.
The angular speed can be calculated by
ω = 2πf
Hence,
ω² = k / m
(2πf)² = k / m
k = (2πf)² / m
where f is frequency.
From the question above, we know that:
m1 = 0.6 kg
f1 = 3 Hz
m2 = 0.38 kg
The spring is same, hence the spring constant is the same
k1 = k2
(2πf1)² / m1 = (2πf2)² / m2
f1² / m1 = f2² / m2
3² / 0.6 = f2² / 0.38
f2² = 5.7
f2 = 2.39 Hz
Find more on angular speed at: brainly.com/question/6860269
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Answer: all three pots should have the same kind of seed, the same amount of light, and the same amount of water.
Explanation:
If you were to rase to temperature 10c and the heat energy required to rase it 1 c is 4190 j/(kg C). 24g • 4190 j/(kg C) • (35-25)C 24 • 4190 • 10= 1,005,600 j or 1.5 MJ
Answer:
<em>11.a) </em><em>Car B </em><em>is faster than </em><em>Car A</em><em>. This is because Car B covers more distance in less time, whereas Car A covers less distance in more time. Now, as we know that distance is directly proportional and time is inversely proportional to speed. In Car B, a larger distance and less time and a smaller distance and more time in Car A, indicates that the speed of Car B is more than the speed of Car A.</em>
<em>b) </em><em>Car B</em><em> accelerates faster than </em><em>Car A. </em><em>We know that, the acceleration is directly proportional to the change in linear velocity and inversely proportional to time taken. Here, The overall journey of </em><em>Car B </em><em>is short, whereas for </em><em>Car A, </em><em>it's longer. Also, as previously mentioned that the final speeds of Car B is more than Car A [remembering that both Cars start from the origin(rest)]. Hence, the change of velocity in Car B is more than Car A. Hence so.</em>