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3 years ago

Newtons 2nd law school home and outdoors examples

1 answer:

7 0

Newton’s second law defines the relationship between the change in the speed of a moving object -- its acceleration -- and the force acting upon it. This force equals the object’s mass multiplied by its acceleration. It takes a smaller extra force to propel a small yacht at sea than to propel a supertanker because the latter has a greater mass than the former.

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Equal amounts of heat are added to equal masses of ice and copper at the same initial temperature. Which substance will have the

pychu [463]

One of the major effects of heat transfer is temperature change: heating increases the temperature while cooling decreases it. We assume that there is no phase change and that no work is done on or by the system. Experiments show that the transferred heat depends on three factors—the change in temperature, the mass of the system, and the substance and phase of the substance.

Figure a shows a copper-colored cylinder of mass m and temperature change delta T. The heat Q, shown as a wavy rightward horizontal arrow, is transferred to the cylinder from the left. To the right of this image is a similar image, except that the heat transferred Q prime is twice the heat Q. The temperature change of this second cylinder, which is also labeled m, is two delta T. This cylinder is surrounded by small black wavy lines radiating outward. Figure b shows the same two cylinders as in Figure a. The left cylinder is labeled m and delta T and has a wavy heat arrow pointing at it from the left that is labeled Q. The right cylinder is labeled two m and delta T and has a wavy heat arrow pointing to it from the left labeled Q prime equals two Q. Figure c shows the same copper cylinder of mass m and with temperature change delta T, with heat Q being transferred to it. To the right of this cylinder, Q prime equals ten point eight times Q is being transferred to another cylinder filled with water whose mass and change in temperature are the same as that of the copper cylinder.

7 0

3 years ago

A 65.0-Ω resistor is connected to the terminals of a battery whose emf is 12.0 V and whose internal resistance is 0.5 Ω. Calcula

Luda [366]

Answer:

a) 0.1832 A

b) 11.91 Volts

c) 2.18 Watt , 0.0168 Watt

Explanation:

(a)

R = external resistor connected to the terminals of the battery = 65 Ω

E = Emf of the battery = 12.0 Volts

r = internal resistance of the battery = 0.5 Ω

i = current flowing in the circuit

Using ohm's law

E = i (R + r)

12 = i (65 + 0.5)

i = 0.1832 A

(b)

Terminal voltage is given as

$V_{ab}$ = i R

$V_{ab}$ = (0.1832) (65)

$V_{ab}$ = 11.91 Volts

(c)

Power dissipated in the resister R is given as

$P_{R}$ = i²R

$P_{R}$ = (0.1832)²(65)

$P_{R}$ = 2.18 Watt

Power dissipated in the internal resistance is given as

$P_{r}$ = i²r

$P_{r}$ = (0.1832)²(0.5)

$P_{r}$ = 0.0168 Watt

5 0

3 years ago

The hydrogen and helium under the clouds of Jupiter are in liquid form due to _____.

asambeis [7]

high pressure produced by the clouds because its the most likely!!!!!!!!!!

8 0

4 years ago

Read 2 more answers

Two bulbs marked 200 W-250 V and 100 W-250 V are joined in

lozanna [386]

Answer:

P = 66.67 W

Explanation:

Joule Heating

It's the process by which the electric current passing through a conductor produces heat.

Also known as Joule's first law or the Joule–Lenz law, states that the power of heating generated by an electrical conductor (P) is proportional to the product of its resistance (R) and the square of the current (I).

It can be described by the equation that follows:

$P = I^2.R$

Also, we can calculate the voltage V with the formula of Ohm's law:

$V = I.R$

Combining both equations, power can be related to the voltage:

$\displaystyle P=\frac{V^2}{R}$

Given the power and the voltage, the resistance can be calculated by solving for R:

$\displaystyle R=\frac{V^2}{P}$

There are two bulbs marked P=200W V=250V and P=100 W V=250.

The first bulb has a resistance of:

$\displaystyle R_1=\frac{250^2}{200}$

$\displaystyle R_1=312.5\Omega$

The first bulb has a resistance of:

$\displaystyle R_2=\frac{250^2}{100}$

$\displaystyle R_1=625\Omega$

When connected in series, the total resistance is

$R = R_1 + R_2=312.5\Omega+625\Omega$

$R=937.5\Omega$

The total power consumed when connecting them to a V=250 V supply is:

$\displaystyle P=\frac{250^2}{937.5}$

P = 66.67 W

4 0

3 years ago

A mass on the end of a spring undergoes simple harmonic motion. At the instant when the mass is at its equilibrium position, wha

Paha777 [63]

Answer:

3.At equilibrium, its instantaneous velocity is at maximum

Explanation:

The motion of a mass on the end of a spring is a simple harmonic motion. In a simple harmonic motion, the total mechanical energy of the system is constant, and it is sum of the elastic potential energy (U) and the kinetic energy of the mass (K):

$E=U+K=\frac{1}{2}kx^2+\frac{1}{2}mv^2 = const.$

where

k is the spring constant

x is the displacement of the spring from equilibrium

m is the mass

v is the speed

As we see from the formula, since the total energy E is constant, when the displacement (x) increases, the speed (v) increases, and viceversa. Therefore, when the mass is at its equilibrium position (which corresponds to x=0), the velocity of the mass will be maximum.

7 0

3 years ago