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4 years ago

The Pilot of a plane measures an air velocity of 165Km/h south relative to the plane. An observer on

1 answer:

6 0

The speed obtained by the pilot is not accurate since it is measuring the rate of travel in the wind, true velocity is that compared to the ground. Therefore the speed of the wind is:

v wind = 165 - 145

v wind = 20 km/h

Therefore the wind velocity = 20 km/h against the plane.

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A stone is launched straight up by a slingshot. Its initial speed is 19.6 m/s, and the stone is 1.50 m above the ground when lau

arlik [135]

Answer: a) 19.21m b) 3.92secs

Explanation:

a) Maximum height reached by the object is the height reached by an object before falling freely under gravity.

Maximum height = U²/2g

U is the initial velocity = 19.6m/s

g is acceleration due to gravity = 10m/s²

Maximum Height = 19.6²/2(10)

H = 19.21m

b) The time elapsed before the stone hits the ground is the time of flight T= 2U/g

T= 2(19.6)/10

T = 39.2/10

Time elapsed is 3.92secs

5 0

3 years ago

A diffraction pattern forms when light passes through a single slit. The wavelength of the light is 691 nm. Determine the angle

expeople1 [14]

Explanation:

Given that,

Wavelength of the light, $\lambda=691\ nm=691\times 10^{-9}\ m$

(a) Slit width, $a=3.8\times 10^{-4}\ m$

The angle that locates the first dark fringe is given by :

$sin\theta=\dfrac{\lambda}{a}$

$sin\theta=\dfrac{691\times 10^{-9}}{3.8\times 10^{-4}}$

$\theta=0.104^{\circ}$

(b) Slit width, $a=3.8\times 10^{-6}\ m$

The angle that locates the first dark fringe is given by :

$sin\theta=\dfrac{\lambda}{a}$

$sin\theta=\dfrac{691\times 10^{-9}}{3.8\times 10^{-6}}$

$\theta=10.47^{\circ}$

Hence, this is the required solution.

7 0

4 years ago

The OBD-II catalytic converter monitor uses _______ sensor(s) to monitor catalytic converter efficiency.

oksano4ka [1.4K]

C comment for an explanation

8 0

3 years ago

You are doing x-ray diffraction on a crystal that has a cubic structure, using 0.340-nm x rays. Part A If the lattice spacing is

Mrac [35]

Answer:

∅ = 0.26°

Explanation:

Bragg's law states that:

n×λ = 2×d×sin(∅)

where:

d is the lattice spacing.
λ is the wavelength of the rays.
n is the order of the diffracted rays, n = 1.

then:

sin(∅) = λ/2×d

∅ = sin^-1(λ/2×d)

∅ = 0.26°

6 0

3 years ago

Consider an electromagnetic wave of frequency f=3x10^6 Hz. does this radiation belong to the visible range to the ultraviolet or

In-s [12.5K]

Answer:

eeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeee

Explanation:

44e

3 0

3 years ago