1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
sdas [7]
3 years ago
7

Help it’s homework!!!!

Mathematics
1 answer:
Airida [17]3 years ago
3 0

Answer:

(3x - 3)(x + 2)

Step-by-step explanation:

3x^2 + 3x - 6

(3x^2 + 6x)(-3x - 6)

3x(x + 2) -3(x + 2)

(3x - 3)(x + 2)

You might be interested in
Joel spends 272727 more minutes playing soccer after school on Tuesday than he did on Monday. He still exercises for a total of
Nookie1986 [14]

Joel spent 72.5% of his time exercising after playing soccer on Tuesda

<h3>How to determine the percentage?</h3>

The given parameters are

Minutes spent on Tuesday = 27 more minutes than Monday

Total minutes spend = 60

This means that

Tuesday = Monday + 27

Monday + Tuesday = 60

Make Monday the subject in Tuesday = Monday + 27

Monday = Tuesday - 27

Substitute Monday = Tuesday - 27 in Monday + Tuesday = 60

Tuesday - 27 + Tuesday = 60

Evaluate

2 * Tuesday = 87

Divide by 2

Tuesday = 43.5

The percentage of time spent exercising on Tuesday is then calculated as

Percentage = 43.5/60 * 100%

Evaluate the expression

Percentage = 72.5%

Hence, Joel spent 72.5% of his time exercising after playing soccer on Tuesday

Read more about percentages at:

brainly.com/question/843074

#SPJ1

6 0
2 years ago
Mei has 8 jars of soup. Each jar contains 300 milliliters of soup. What is the smallest pot Mei can use to heat all the soup.[PL
Kobotan [32]

Answer: A pot of 2400ml

Step-by-step explanation: Ok, mei has 8 jars, and each jar has 300ml of soup, so the total amount of soup is 8 times 300ml

N = 8*300ml = 2400ml

So the smallest pot that mei can use to heat the soup is a pot that has exactly that volume. 2400ml, (discarding the fact that the volume of the soup will change as it is heated up)

7 0
3 years ago
Which of the following do you use to tell whether a relationship is<br> proportional or not?
Setler79 [48]

Answer:

The correct option to tell whether a relationship is proportional or not is;

\dfrac{y}{x}

Step-by-step explanation:

A proportional relationship is a relationship between two variables, 'x', and 'y' such that they have equivalent ratio, such that all values of variable 'y' are given by the product of the values of the variable 'x' and a constant, 'k'

Therefore, y = k · x, from which we have;

\dfrac{y}{x} = k = Contant

Therefore we can use \dfrac{y}{x} to tell whether a relationship is proportional or not proportional.

6 0
3 years ago
Helpppppppppp giveing brainlist
Grace [21]
A/D plz give brain!!! :).
7 0
3 years ago
Read 2 more answers
Jazzmin has 2/5 of a pie. How many 1/10's of a whole pie are there in 2/5 of a whole pie?
Svetllana [295]

Answer:

4/10

Step-by-step explanation:

when converting fractions, you multiply the numerator and the denominator by the same number. In this case, multiply it by 2, giving you 4/10.

8 0
3 years ago
Other questions:
  • What is the slope of 2,000=20×+10y?
    13·2 answers
  • With a short time remaining in the​ day, a delivery driver has time to make deliveries at 7 locations among the 9 locations rema
    7·1 answer
  • If a b and c d which pair of angles are congruent
    12·1 answer
  • How do i do this im confused
    6·2 answers
  • Write a related addition fact for 15-6 = 9
    13·2 answers
  • <img src="https://tex.z-dn.net/?f=%208%20%5Cfrac%7B7%7D%7B9%7D%20%20%2B%204%20%20%5Cfrac%7B1%7D%7B8%7D%20" id="TexFormula1" titl
    5·2 answers
  • The number 64 is a perfect ___<br><br> A. Square<br><br> B. Cube<br><br> C. Both
    15·2 answers
  • 1/7 + 6/7 equals1/7 + 6/7 equals
    8·2 answers
  • The equation f(x) = 2x²-x+ 4 has roots a and B.
    13·1 answer
  • John is buying a TV that costs $1250. He currently has $200 saved and is
    14·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!