Help it’s homework!!!!
1 answer:
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Interesting way to teach this problem. I'll see if I can make a table that answers the question as it is presented.
Now all you need do is collect the nine terms from the table and put the like ones together if there are any.
Interesting way to teach this problem. I'll see if I can make a table that answers the question as it is presented.
Now all you need do is collect the nine terms from the table and put the like ones together if there are any.
Answer:
The points of intersections are: <u>(1.5 , 1.25) and (4 , 0)</u>
Step-by-step explanation:
Given:
y = x² - 6x + 8 ⇒ (1)
2y + x = 4 ⇒ (2)
And required the solution of the system of equations.
By graphing the system of equations, the points of intersections are:
<u>(1.5 , 1.25) and (4 , 0)</u>
See the attached figure.
<u>Another solution:</u>
By substitution of y from the second equation at the first equation.
From (1) ⇒ y = 0.5 (4-x)
At (2): and solve for x
0.5 ( 4 - x ) = x² - 6x + 8 ⇒ multiply both sides by 2
4 - x = 2x² - 12x + 16
2x² - 12x + 16 + x - 4 = 0
2x² - 11x + 12 = 0
The general solution of the quadratic equation:
so, a = 2 , b = -11 and c = 12
∴
∴ at x = 4 ⇒ y = 0.5 (4-x) = 0.5 * 0 = 0
And at x = 1.5 ⇒ y = 0.5 (4-x) = 0.5 * ( 4 - 1.5 ) = 0.5 * 2.5 = 1.25
<u>So, the solution are the points (4,0) and (1.5 , 1.25)</u>
