Answer:
The magnitude of the net current = 18 A.
Direction of the net current is along the negative z axis.
Explanation:
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<u><em>Given:</em></u>
- Number of electrons flow through the given cross section,
- Number of electrons flow through the given cross section,
- Time interval for which the electrons and protons flow,
The current through a cross section is defined as the amount of charge passing through that cross section in unit time.
We know,
Charge on an electron,
Charge on a proton,
Therefore,
The amount of charge flowing due to electrons is given by
The amount of charge flowing due to protons is given by
The current flowing through the cross section because of the electrons is given as:
The negative sign shows that the current is due to the flow of negative charge, and the direction of current is always opposite to that of flow of negative charge i.e., electrons.
Thus, the direction of this current is along the negative z direction.
The magnitude of this current = 12 A.
The current flowing through the cross section because of the protons is given as:
The direction of this current is same as that of electrons,
The directions of the currents due to both, the electrons and the protons are along the negative z direction, therefore the magnitude of the net current is given as:
Answer:
d= 7.32 mm
Explanation:
Given that
E= 110 GPa
σ = 240 MPa
P= 6640 N
L= 370 mm
ΔL = 0.53
Area A= πr²
We know that elongation due to load given as
A= 42.14 mm²
πr² = 42.14 mm²
r=3.66 mm
diameter ,d= 2r
d= 7.32 mm
translation:
The period of oscillation of a pendulum is 4 seconds calculate the value of the frequency.
Lo siento, pero no puedo responder a tu pregunta.
(también la gente informará si lo hace en inglés mentalmente en un idioma diferente, así que ... tal vez traducir)
Answer is a.)
Given: Mass m = 70 Kg Height h = 10 m; g = 10 m/s²
Required. Gravitational Potential Energy or P.E
Formula: P.E = mgh
= (70 Kg)(10 m/s²)( 10 m)
P.E = 7,000 Kg.m²/s² or
P.E = 7,000 J
Answer:
60.46°
Explanation:
Given that, the wavelength of yellow light which is falling on grating is,
The angle is of the order of 3 means m=3.
And number of lines per mm is,
Therefore the condition of maxima,
Here,
And for third order maxima, m=3
Therefore,
Therefore, the angle for third order maxima is 60.46°.