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3 years ago

A stone is dropped from a cliff. after it has fallen 10m what is the stones velocity

Physics

2 answers:

Hatshy [7]3 years ago

6 0

Answer:

V=14,1421 m/s

Explanation:

it's simple.

Velocity increases with the gravity acceleration.

There's a formula called Torricelli's equation, and it is as it follows:

V^2 = Vo^2 +2.a.s

where V is the speed you wish to find

Vo is the initial speed

a is the acceleration, in this case, the gravity's one

s is the space it moved.

So, here we go

Vo=0

a=10 or 9.81 (some schools use 10 to simplify the math)

s=10

So, using g as 10

V^2 = 0 +2.10.10

V^2=200

V=14,1421 m/s

Ludmilka [50]3 years ago

3 0

The answer is 14,1421 m/s. :)

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3 years ago

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A basketball is held over head at a height of 2.4 m. The ball is lobbed to a teammate at 8 m/s at an angle of 40'. If the ball i

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since both the teammates are of the same height, their height won't matter. Because now the basketball won't cover any vertical distance.

We have to calculate its range the horizontal distance covered by it when tossed from one teammate to the other.

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$\boxed{\mathfrak{range = \frac{ u {}^{2} \sin 2\theta }{g} }}$

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3 years ago

QUICK PLZ I NEED TO TURN IT IN

Anni [7]

The answer i got is 133.3 but i’m not completely sure . I got that because to get velocity i’m pretty sure it’s distance over time. So in between 8 and 10 minutes it’s 9 minutes. I pretty much just did 1200 divided by 9.

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4 years ago

the reading on a mercury barometer at mombasa is 760mms.calculate the pressure at mombasa(density of mercury=1.36x10 power 4kg/m

Vikentia [17]

Answer:

The pressure at Mombasa is 101.396 KPascal.

Explanation:

Given: Reading on barometer = 760 mm

= 0.76 m

Density of mercury = 1.36 x $10^{4}$ kg/ $m^{3}$

In this case, the pressure can be expressed as:

P = σhg

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3 years ago