A stone is dropped from a cliff. after it has fallen 10m what is the stones velocity
2 answers:
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Answer:
the magnitude of the displacement after 5s is 137.31 m.
Explanation:
Given;
initial velocity of the projectile, u = 60 m/s
angle of projection, θ = 60°
time of motion, t = 5s
the vertical component of the velocity,
The magnitude of the displacement after 5s is calculated as;
Therefore, the magnitude of the displacement after 5s is 137.31 m.
Answer:
The average velocity is 40km/h.
Explanation:
The average velocity is , where
is the distance traveled and
the time elapsed.
The distance traveled is clearly 80km since it's all done in the same direction, we only need to know the time elapsed. For this we calculate the time elapsed on the first part, and add it to the time elapsed on the second part using always the formula , where v is the velocity on each part, which is constant.
The time elapsed for the first part is , and the time elapsed for the second part is
, giving us a total time of
=2h.
Finally, we can calculate the average velocity: .