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torisob [31]
3 years ago
8

A stone is dropped from a cliff. after it has fallen 10m what is the stones velocity

Physics
2 answers:
Hatshy [7]3 years ago
6 0

Answer:

V=14,1421 m/s

Explanation:

it's simple.

Velocity increases with the gravity acceleration.

There's a formula called Torricelli's equation, and it is as it follows:

V^2 = Vo^2 +2.a.s

where V is the speed you wish to find

Vo is the initial speed

a is the acceleration, in this case, the gravity's one

s is the space it moved.

So, here we go

Vo=0

a=10 or 9.81 (some schools use 10 to simplify the math)

s=10

So, using g as 10

V^2 = 0 +2.10.10

V^2=200

V=14,1421 m/s

Ludmilka [50]3 years ago
3 0
The answer is 14,1421 m/s. :)
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Answer: 6.24 km

Explanation:

Given

The magnitude of the first vector(say) \left |  a\right |=5\ km

the magnitude of the second vector(say) \left |  b\right |=7\ km

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The resultant vector magnitude is given by

\left |  \vec{R}\right |=\sqrt{a^2+b^2+2ab\cos \theta}

\left |  \vec{R}\right |=\sqrt{5^2+7^2+2\times 5\times 7\cdot \cos 120^{\circ}}\\\left |  \vec{R}\right |=\sqrt{74-35}=\sqrt{39}\\\left |  \vec{R}\right |=6.24\ km

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2 years ago
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2 years ago
Given that water at standard pressure freezes at 0∘C, which corresponds to 32∘F, and that it boils at 100∘C, which corresponds t
barxatty [35]

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