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3 years ago

Arrange the numbers from least to greatest. -13 , -5/4 , 2 ½ , 5 ¼

Mathematics

1 answer:

Archy [21]3 years ago

8 0

-13 -5/4 2 1/2 5 1/2

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How would i solvd this problem as sn improper fraction 2 1/8

zmey [24]

17/8..........................................

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3 years ago

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Test the series for convergence or divergence (using ratio test)

Triss [41]

Answer:

$\lim_{n \to \infty} U_n =0$

Given series is convergence by using Leibnitz's rule

Step-by-step explanation:

Step(i):-

Given series is an alternating series

∑ $(-1)^{n} \frac{n^{2} }{n^{3}+3 }$

Let $U_{n} = (-1)^{n} \frac{n^{2} }{n^{3}+3 }$

By using Leibnitz's rule

$U_{n} - U_{n-1} = \frac{n^{2} }{n^{3} +3} - \frac{(n-1)^{2} }{(n-1)^{3}+3 }$

$U_{n} - U_{n-1} = \frac{n^{2}(n-1)^{3} +3)-(n-1)^{2} (n^{3} +3) }{(n^{3} +3)(n-1)^{3} +3)}$

Uₙ-Uₙ₋₁ <0

Step(ii):-

$\lim_{n \to \infty} U_n = \lim_{n \to \infty}\frac{n^{2} }{n^{3}+3 }$

$= \lim_{n \to \infty}\frac{n^{2} }{n^{3}(1+\frac{3}{n^{3} } ) }$

= $= \lim_{n \to \infty}\frac{1 }{n(1+\frac{3}{n^{3} } ) }$

$=\frac{1}{infinite }$

$\lim_{n \to \infty} U_n =0$

∴ Given series is converges

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3 years ago

What is the remainder when 2x^3−9x^2+11 is divided by x−6?

zheka24 [161]

Answer:

119

Step-by-step explanation:

Given f(x) divided by (x - h) then the value of f(h) is the remainder, thus

f(6) = 2(6)³ - 9(6)² + 11

= 2(216) - 9(36) + 11

= 432 - 324 + 11

= 119 ← remainder

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2 years ago

Jesse and mark are jogging along the route shown at a rate of 12 miles per hour. they start by jogging south along capitol stree

kotykmax [81]

Answer:

12457

Step-by-step explanation:

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2 years ago

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1. WRUF 103.7 FM is giving away tickets to a concert. Tim, the general manager of the

Eva8 [605]

Answer:

Kindly check explanation

Step-by-step explanation:

Given that :

Upper level seat = $25

Mid level seat = $40

Number of tickets to give away is at least 25

Budget constraint = $1000

part A: write a system of two inequalities that describe this situation

Number of tickets constraint:

Upper level + mid level ≥ 25

u + m ≥ 25

Cost constraint :

$25u + $40m ≤ $1000

Part B:

Give away 10 upper level seat tickets and 15 mid level seat tickets

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3 years ago