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Reil [10]
3 years ago
7

The sum of two

Mathematics
1 answer:
sergeinik [125]3 years ago
8 0

Answer:

63

Step-by-step explanation:

let the two numbers be x,y (x>y)

Then x+y = 16 and x-y = 2

We know that (x+y)^2 - (x-y)^2 = 4xy

So 4xy = 16^2 - 2^2 => 4xy = (16+2)(16–2)

So xy = 18×14/4 = 63

Product of the numbers = 63

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What is the value of the function at x=−2?
kogti [31]

So for this problem, the x-axis is the horizontal line in the center.

Go to where -2 is on the x-axis as shown. Use your finger to trace along since that's usually helpful in finding the point.

Move your finger from -2 on the x-axis to where the solid black line is. On the right side of that, you can see that the y-axis holds the number 2 which is what the y equals for this solid line.

Therefore, the answer should be c.) y = 2

8 0
3 years ago
Three single-digit numbers multiply to make 504 Write the missing numbers
boyakko [2]
We will guess and check to solve this problem

504/9= 56
504/8= 63
504/7= 72
504/6= 84
.....
we can continue the pattern. However, we know that 50 is the product of 8 and 7, so we can use that number

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3 0
3 years ago
Use the "rule of 72" to estimate the doubling time (in years) for the interest rate, and then calculate it exactly. (Round your
Law Incorporation [45]

Answer:

According to the rule of 72, the doubling time for this interest rate is 8 years.

The exact doubling time of this amount is 8.04 years.

Step-by-step explanation:

Sometimes, the compound interest formula is quite complex to be solved, so the result can be estimated by the rule of 72.

By the rule of 72, we have that the doubling time D is given by:

D = \frac{72}{Interest Rate}

The interest rate is in %.

In our exercise, the interest rate is 9%. So, by the rule of 72:

D = \frac{72}{9} = 8.

According to the rule of 72, the doubling time for this interest rate is 8 years.

Exact answer:

The exact answer is going to be found using the compound interest formula.

A = P(1 + \frac{r}{n})^{nt}

In which A is the amount of money, P is the principal(the initial sum of money), r is the interest rate(as a decimal value), n is the number of times that interest is compounded per unit t and t is the time the money is invested or borrowed for.

So, for this exercise, we have:

We want to find the doubling time, that is, the time in which the amount is double the initial amount, double the principal.

is double the initial amount, double the principal.

A = 2P

r = 0.09

The interest is compounded anually, so n = 1

A = P(1 + \frac{r}{n})^{nt}

2P = P(1 + \frac{0.09}{1})^{t}

2 = (1.09)^{t}

Now, we apply the following log propriety:

\log_{a} a^{n} = n

So:

\log_{1.09}(1.09)^{t} = \log_{1.09} 2

t = 8.04

The exact doubling time of this amount is 8.04 years.

4 0
3 years ago
What fraction of the months of the year have 31 days
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nata0808 [166]

Answer:

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Step-by-step explanation:

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