Answer:
The mean and the standard deviation of the sampling distribution of the number of students who preferred to get out early are 0.533 and 0.82
Step-by-step explanation:
According to the given data we have the following:
Total sample of students= 150
80 students preferred to get out 10 minutes early
Therefore, the mean of the sampling distribution of the number of students who preferred to get out early is = 80/150 = 0.533
Therefore, standard deviation of the sampling distribution of the number of students who preferred to get out early= phat - p0/sqrt(p0(1-p)/)
= 0.533-0.5/sqrt(0.5*0.5/15))
= 0.816 = 0.82
Answer:
please can you indicate the question
Answer:
0.9 1.8 2.9
Step-by-step explanation:
In order to graph the relationship, we will need to write the expression as the equation of a straight line as shown:
d = mt + b
d is the distance covered
t is the time taken
m is the speed
If you are skateboarding at a pace of 30 meters every 5 seconds. your friend is in-line skating at a pace of 9 meters every 2 seconds, this can be written as (5, 30) and (2, 9)
Get the slope of the line:
m = (9-30)/(2-5)
m = -21/-3
m = 7
Substitute m = 7 and the coordinate (2, 9) into the equation y = mt + b
9 = 7(2) + b
9 = 14 + b
b = -5
The required equation to plot will be expressed as y = 7t - 5
Plot the required graph
Learn more here: brainly.com/question/17003809