The volume of a pyramid can be calculated as:
Where B is the area of the base and H is the height. We are given V = 60 cubic inches and H = 5 inches. Solving for B:
Substituting:
The area of the base is 36 square inches.
We must choose the option whose area is 36 sq in.
A square of a side length of 6 inches has an area of:
Thus, the correct choice is D.
Answer:
-3 5/12=k
Step-by-step explanation:
K+5/3= -7/4
subtract 5/3 from both sides
K= -7/4-5/3
lcm of 4 and 3 is 12
so
K= -21/12-20/12
K= -41/12
K= -3 5/12
This can be solved a couple of ways. One way is to use the Pythagorean theorem to write equations for the magnitude from the components of the forces. That is what was done in the graph here.
Another way is to use the Law of Cosines, which lets you make direct use of the angle between the vectors.
.. 13 = a^2 +b^2 -2ab*cos(90°)
.. 19 = a^2 +b^2 -2ab*cos(120°)
Subtracting the first equation from the second, we have
.. 6 = -2ab*cos(120°)
.. ab = 6
Substituting this into the first equation, we have
.. 13 = a^2 +(6/a)^2
.. a^4 -13a^2 +36 = 0
.. (a^2 -9)(a^2 -4) = 0
.. a = ±3 or ±2
The magnitudes of the two forces are 2N and 3N, in no particular order.
Answer:
1
Step-by-step explanation:
- 3/5 divided by 12/20 = 3/5 * 20/12 = 60/60 = 1
We can set up 2 equations given the information.
Let the price of advance ticket be represented by A and same day ticket by S
A + S = 50
20A + 40S = 1700
Solve for A in the first equation by subtracting S on both sides.
U will get A = 50 - S
Now substitute 50 - S for A in the second equation.
20 (50 - S) + 40S = 1700
1000 - 20S + 40S = 1700
20S = 700
S = 35
Same day ticket costs $35 and advance ticket costs $15
