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Alekssandra [29.7K]
2 years ago
5

If a certian perosn has a mass of 250kg on earth, would that person's mass be on the moon, if the moon's gravity is 1.62m/s2? *

Mathematics
1 answer:
IceJOKER [234]2 years ago
6 0

Answer:

Weight On the Moon: 41.34 kilograms

Step-by-step explanation:

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Read 2 more answers
Tickets to a concert cost either $12 or $15. A
olga_2 [115]

Answer:

  • 12x +15y = 4140; x + y = 300
  • x = 120; y = 180

Step-by-step explanation:

The first equation is for receipts. Each x ticket generated $12 in receipts, so the first term needs to be 12x. Each y ticket generated $15 in receipts, so the second term needs to be 15y. U in this set of equations is the total number of tickets, said to be 300.

The equations are ...

  12x +15y = 4140; x +y = 300

__

Using the second equation to write an expression for x, we have ...

  x = 300 -y

Substituting this into the first equation gives ...

  12(300 -y) +15y = 4140

  3600 +3y = 4140

  y = (4140 -3600)/3 = 180

  x = 300 -180 = 120

The number of tickets sold is ...

  $12 tickets -- 120

  $15 tickets -- 180

_____

You might want to notice that the equation we ended up with:

  4140 -12(300) = 3y

is equivalent to this "word solution." This can be done in your head; no equations required.

If all the tickets sold were $12 tickets, the revenue would be $3600. The revenue is $540 more than that. Each $15 ticket generates $3 more revenue than a $12 ticket, so to have $540 more revenue, we must have 540/3 = 180 $15 tickets.

6 0
3 years ago
Point Q is equidistant from AB and AC. What must be true about Q?
vagabundo [1.1K]

Answer:

D. It is on the angle bisector of ∠BAC

Step-by-step explanation:

Given that point Q is equidistant from AB and AC. This implies that AB and AC forms an angle BAC i.e <BAC. An equidistant point is a point that has the same distance from two different reference points.

Bisection is the process by which a line or angle is divided into two equal parts. A line that passes through the point of division is called a bisector, which is of equal distance to either of the reference points.

Thus by construction, a point that would be of equal distance to AB and AC is on an angle bisector of <BAC. So that point Q is on the angle bisector of <BAC.

3 0
3 years ago
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