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3 years ago

Solve the equation: x÷2<4 and then graph it

Mathematics

1 answer:

ankoles [38]3 years ago

6 0

I think the answer is eight.

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Need help finding out what 3x=y and x-2y = 10

sweet-ann [11.9K]

Answer:

x=-2, y=-6

Step-by-step explanation:

Simple substitution.

Since y is isolated in one of the equations already, you can plug it into the second equation.

x - 2(3x) = 10

x - 6x = 10

-5x = 10

x = -2

Sub. x = -2 into 3x = y:

3(-2) = y

y = -6

4 0

3 years ago

Can you answer this for me plssss 0.5(r+2.75)=3

lora16 [44]

Step-by-step explanation:

0.5 ( r + 2.75 ) = 3

r + 2.75 = 3 / 0.5

r + 2.75 = 6

r = 6 - 2.75

r = 3.25

4 0

3 years ago

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On Sunday, chara ran 6 more miles than he did on Saturday. If he ran m miles on Saturday, which expression represents how many m

sattari [20]

Answer:

Is A supposed to be 6 x m or no??

Step-by-step explanation:

8 0

3 years ago

Simplify the expression.

Marizza181 [45]

$\bf \textit{Cofunction Identities}
\\ \quad \\
sin\left(\frac{\pi}{2}-{{ \theta}}\right)=cos({{ \theta}})\qquad 
\boxed{cos\left(\frac{\pi}{2}-{{ \theta}}\right)=sin({{ \theta}})}
\\ \quad \\ \quad \\
tan\left(\frac{\pi}{2}-{{ \theta}}\right)=cot({{ \theta}})\qquad 
cot\left(\frac{\pi}{2}-{{ \theta}}\right)=tan({{ \theta}})
\\ \quad \\ \quad \\
sec\left(\frac{\pi}{2}-{{ \theta}}\right)=csc({{ \theta}})\qquad 
csc\left(\frac{\pi}{2}-{{ \theta}}\right)=sec({{ \theta}})$

$\bf \\\\
-------------------------------\\\\
sin^2(\theta)+cos^2(\theta)=1\implies cos^2(\theta)=1-sin^2(\theta )
\\\\\\
\boxed{cos(\theta )=\sqrt{1-sin^2(\theta )}}$

$\bf \\\\
-------------------------------\\\\
\cfrac{cos^2\left(\frac{\pi }{2}-x \right)}{\sqrt{1-sin^2(x)}}\implies \cfrac{\left[ cos\left(\frac{\pi }{2}-x \right)\right]^2}{cos(x)}\implies \cfrac{[sin(x)]^2}{cos(x)}\implies \cfrac{sin(x)sin(x)}{cos(x)}
\\\\\\
sin(x)\cdot \cfrac{sin(x)}{cos(x)}\implies sin(x)tan(x)$

6 0

3 years ago

2x + 10x find equivalent expression

snow_tiger [21]

It's 12x. you just combine both numbers

8 0

3 years ago

Read 2 more answers