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3 years ago

How many different arrangements can be made with the letters in the word POWER?

2 answers:

eduard3 years ago

4 0

Slot meathod

5 lettters with 5slots

1st slot has 5 choices
2nd slot has 4 (1 went to first slot)
3rd slot has 3
2hd has 2
1st has 1

multiply them together
5*4*3*2*1=120

answer is 120 arangements

vladimir2022 [97]3 years ago

3 0

129 arrangements can be made 5 x 4 x 3 x 2 x 1= 120

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54=3q show work and step by step

MaRussiya [10]

Divide 54 by 3 which will get you q=18

7 0

3 years ago

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Find h(x, y) = g(f(x, y)). g(t) = t + ln(t), f(x, y) = 4 − xy 2 + x2y2 h(x, y) =

san4es73 [151]

-2in = the equals sign has a slash through it 0

3 0

2 years ago

PLS HELPP! :)<br><br>What is the radius with a circumference of 122 in?

Mumz [18]

Answer:

this is the answer r≈19.42in

because you radius with a circumference of 122in

and that's your answer

Step-by-step explanation:

hope it works

4 0

2 years ago

Help me plzzzzzzz guyssss

maks197457 [2]

Answer:

1. 75%

2. 20%

3. 20%

4. decrease 5.4%

Step-by-step explanation:

1. 119-68=51, 51/68=0.75

2. 30-24=6, 6/30=0.20

3. 18-15=3, 3/15=0.20

4. 762-721=41, 41/762=0.0538

5 0

2 years ago

Find the surface area of the part of the sphere x2+y2+z2=81 that lies above the cone z=x2+y2−−−−−−√

TiliK225 [7]

Parameterize the part of the sphere by

$\mathbf s(u,v)=(9\cos u\sin v,9\sin u\sin v,9\cos v)$

with $0\le u\le2\pi$ and $0\le v\le\dfrac\pi4$ . Then

$\mathrm dS=\|\mathbf s_u\times\mathbf s_v\|=81\sin v\,\mathrm du\,\mathrm dv$

So the area of $S$ (the part of the sphere above the cone) is given by

$\displaystyle\iint_S\mathrm dS=81\int_{v=0}^{v=\pi/4}\int_{u=0}^{u=2\pi}\sin v\,\mathrm du\,\mathrm dv=81(2\pi)\left(1-\dfrac1{\sqrt2}\right)=(162-81\sqrt2)\pi$

4 0

3 years ago