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Bad White [126]
3 years ago
7

X / -3 = 6 Pls solve.

Mathematics
1 answer:
soldier1979 [14.2K]3 years ago
7 0

Answer:

-18

Step-by-step explanation:

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PLEASE HELP 20! POINTS
mrs_skeptik [129]

X1= -3/2

X2= 0

F(x)=4x^2+6x

To find X-intercept/zero, substitute f(x)=0

0=4x^2+6x

Move the constant to the right

4x^2+6x=0

Factor out 2x from the expression

2x(2x+3)=0

Divide both sides of the equation

2x(2x+3)/2=0/2

X(2x+3)=0

When the product of factors equals 0, at least one factor is 0.

X=0

2x+3=0

Next you solve for X by moving the constant to the right

2x=-3

Then divide both sides by 2

X=-3/2

Hope this answers your question.

3 0
3 years ago
Paulita is buying 4 boxes of fruit loops. she has a coupon for 1.00 off each box. her total bill is 10.36. write and solve an eq
kotykmax [81]
The equation would have to be set up as 4b - 4 = 10.36. This is because you’re buying 4 boxes of fruit loops, and $1 taken off each box is $4 total for all four boxes.
6 0
4 years ago
Evaluate the function f(x) =1/2 x + 3<br> ASAP
Salsk061 [2.6K]

Answer:5

Step-by-step explanation:

f(4)= ((1/2)*4)+3= 2+3=5

3 0
3 years ago
Find the general term of {a_n}
Assoli18 [71]

From the given recurrence, it follows that

a_{n+1} = 2a_n + 1 \\\\ a_{n+1} = 2(2a_{n-1} + 1) = 2^2a_{n-1} + 1 + 2 \\\\ a_{n+1} = 2^2(2a_{n-2}+1) + 1 + 2 = 2^3a_{n-2} + 1 + 2 + 2^2 \\\\ a_{n+1} = 2^3(2a_{n-3} + 1) + 1 + 2 + 2^2 = 2^4a_{n-3} + 1 + 2 + 2^2 + 2^3

and so on down to the first term,

a_{n+1} = 2^na_1 + \displaystyle \sum_{k=0}^{n-1}2^k

(Notice how the exponent on the 2 and the subscript of <em>a</em> in the first term add up to <em>n</em> + 1.)

Denote the remaining sum by <em>S</em> ; then

S = 1 + 2 + 2^2 + \cdots + 2^{n-1}

Multiply both sides by 2 :

2S = 2 + 2^2 + 2^3 + \cdots + 2^n

Subtract 2<em>S</em> from <em>S</em> to get

S - 2S = 1 - 2^n \implies S = 2^n - 1

So, we end up with

a_{n+1} = 4\cdot2^n + S \\\\ a_{n+1} = 2^2\cdot2^n + 2^n-1 \\\\ a_{n+1} = 2^{n+2} + 2^n - 1 \\\\\implies \boxed{a_n = 2^{n+1} + 2^{n-1} - 1}

5 0
3 years ago
On a map, a distance of 2 cm represents 15 km. What is the distance (in km) between two cities that are 11 cm apart on the map?
GenaCL600 [577]

Answer:

82.5 km

Step-by-step explanation:

Given:

\frac{2cm}{15km} =\frac{11cm}{?km}

Cross-multiply.

2x = 11(15)

Divide both sides by 2 and solve for x.

x = 82.5 km

Please mark as Brainliest! :)

6 0
3 years ago
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