If you need to substitute the equation x = y - 1.
If you have another equation, then you would plug in y - 1 into the x value of the equation you would need to substitute into.
Hope this helps
<span>lim (x → π/2) (sinx)^(tanx)
= lim (x → π/2) e^[(tanx) ln (sinx)]
= e^ [lim (x → π/2) (tanx) ln (sinx)] ... (1)
lim (x → π/2) (tanx) ln (sinx)
= lim (x → π/2) [ln(sinx) / cotx]
Using L'Hospital'stheorem,
= lim (x → π/2) [- cotx / cosec^2 x]
= 0
Plugging in ( 1 ),
required limit = e^0 = 1
=>Answer is 1.
I hope my answer has come to your help. Thank you for posting your question here in Brainly.
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The answer is “like” terms.
You add common terms together to get variables by themselves.
3a^6 -2a^5 +a^4
Brainly says my answer is too short so I have to add extra text here
she would've had to buy 34 pages
