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Inessa [10]
2 years ago
14

A college administrator claims that the proportion of students that are female is greater than 62%. To test this claim, a random

sample of 300 students is taken and its determined that 213 students are female. The following is the setup for this hypothesis test: {H0:p=0.62Ha:p>0.62 Find the test statistic for this hypothesis test for a proportion. Round your answer to 2 decimal places. Provide your answer below: $$
Mathematics
1 answer:
egoroff_w [7]2 years ago
4 0

Answer: 3.21

Step-by-step explanation:

As per given description, we have

Population proportion : p=0.62

Sample size : n= 300

Sample proportion : \hat{p}=\dfrac{213}{300}=0.71

Test statistic for population proportion :-

z=\dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}}\\\\\\=\dfrac{0.71-0.62}{\sqrt{\dfrac{0.62(1-0.62)}{300}}}\\\\=3.21155595947\ \ \\\\\approx3.21 \ \ \text{[Rounded to 2 decimal places. ]}

Hence, the test statistic for this hypothesis test for a proportion= 3.21

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sdas [7]
The radical equation is \sqrt{x+6}-5=x+1.


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iii) Collecting the variables on the same side, and factorizing t we have:
 
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Answer: <span>x = −6 and x = −5 </span>
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