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sergeinik [125]
3 years ago
9

Two polygons are similar. What is the correct similarity statement?​

Mathematics
2 answers:
joja [24]3 years ago
6 0

Answer:

option 3

Step-by-step explanation:

Given the 2 triangles are similar then corresponding angles are congruent.

Calculate the missing angles in both triangles.

∠ A = 180° - (90 + 35)° = 180° - 125° = 55°

∠ L = 180° - (90 + 55)° = 180° - 145° = 35°

Consider ACB ~ MNL , comparing corresponding angles

∠ A= 55° and ∠ M = 90° ← not congruent

Consider ABC ~ LMN, comparing corresponding angles

∠ A = 55° and ∠ L = 35° ← not congruent

Consider CBA ~ LMN , comparing corresponding angles

∠ C = 35° and ∠ L = 35° ← congruent

∠ B = 90° and ∠ M = 90° ← congruent

∠ A = 55° and ∠ N = 55° ← congruent

The correct similarity statement is

CBA ~ LMN

wolverine [178]3 years ago
5 0

Answer:  C) CBA ≅ LMN

<u>Step-by-step explanation:</u>

Match up the congruent angles:

∠C = 35°, ∠L = 90° - 55° = 35°     --> ∠C ≡ ∠L

∠B = 90°, ∠M = 90°                     -->  ∠B ≡ ∠M

∠A = 90° - 35° = 55°, ∠N = 55°    --> ∠A ≡ ∠N

The similarity statement can be written in any order as long as the congruent angles are in the same placement (1st, 2nd, or 3rd).

ΔABC ≅ ΔNML

ΔBCA ≅ ΔMLN

ΔCAB ≅ ΔLNM

ΔCBA ≅ ΔLMN

ΔACB ≅ ΔNLM

ΔBAC ≅ΔMNL

Any of these similarity statements can be used!

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krok68 [10]

Answer:

Dr   Cash/Bank $2,250

Cr   Account Receivable $2,250

Step-by-step explanation:

At the time the transaction was carried out, that is the previous month, the accounting entries was a debit to account receivable (client account) and a credit to sales account. which is as shown below:

<em>Dr   Account Receivable $2,250</em>

<em>Cr   Sales  $2,250</em>

<em>Being sales on credit to a client.</em>

The client account will have an outstanding debit balance of <em>$2,250 </em>until payment is made. once payment is made, the following entries will be made to ensure no outstanding balance in the client account.

Dr   Cash/Bank $2,250

Cr   Account Receivable $2,250.

7 0
2 years ago
Você precisa colocar suas renas, Raposa, Trovão, Cometa e Relâmpago, em uma fila única para puxar o seu trenó. No entanto, Comet
Gennadij [26K]

Answer:

If the reindeer do not fight, there are 5!=120 ways to line them up in a straight line.

Out of these, Bloopin and Rudy are together in 4!=24 times.  Similarly Rudy and Bloopin will be together 4!=24 times.  So the number of ways they are not together is 120-24-24=72 ways.

Hope this helps.    :)

Step-by-step explanation:

Spanish:

Si los renos no luchan, hay 5! = 120 formas de alinearlos en línea recta.

De estos, Bloopin y Rudy están juntos en 4! = 24 veces. De manera similar, Rudy y Bloopin estarán juntos 4! = 24 veces. Entonces, el número de formas en que no están juntas es 120-24-24 = 72 formas.

Espero que esto ayude       :)

4 0
2 years ago
Type the correct answer in each box. If necessary, use / for the fraction bar(s).
Tom [10]

Given:

The values are a=0.\overline{6},b=0.75.

To find:

The values of ab and \dfrac{a}{b}.

Solution:

We have,

a=0.\overline{6}

a=0.666...                     ...(i)

Multiply both sides by 10.

10a=6.666...                 ...(ii)

Subtracting (i) from (ii), we get

10a-a=6.666...-0.666...

9a=6

a=\dfrac{6}{9}

a=\dfrac{2}{3}

And,

b=0.75

b=\dfrac{75}{100}

b=\dfrac{3}{4}

Now, the product of a and b is:

ab=\dfrac{2}{3}\times \dfrac{3}{4}

ab=\dfrac{1}{2}

The quotient of a and b is:

\dfrac{a}{b}=\dfrac{\dfrac{2}{3}}{\dfrac{3}{4}}

\dfrac{a}{b}=\dfrac{2}{3}\times \dfrac{4}{3}

\dfrac{a}{b}=\dfrac{8}{9}

Therefore, the required values are ab=\dfrac{1}{2} and \dfrac{a}{b}=\dfrac{8}{9}.

6 0
3 years ago
Which are acute, obtuse, or right?
qaws [65]
5,7 and 8 are right angles, and 6 is an acute angle this is because of u look at 9 and 10 you can see a little box looking thing under the h and if u do that to all of them 5, 7 and 8 can fit the little box but 6 you can’t because it is an acute angle. Hope this helped!
8 0
3 years ago
Triangle TRE has vertices T(3,6), R(-3,10), and E(-9,4). Find the coordinates of point M if line TM is a median of triangle TRE
Sergeeva-Olga [200]

Answer:

The coordinate of point M = (-6,7)

Explanation:

The Median of a triangle is a line segment from a vertex to the midpoint of the opposite side of a triangle.

Given: \triangle TRE has vertices T(3,6) , R(-3,10) and E(-9,4).

Here, line TM is a median of triangle TRE where M is the midpoint of RE.

The midpoint of  M of the line segment from R(-3,10)  to E(-9,4) is;

M = (\frac{-3+(-9)}{2}, \frac{10+4}{2}) = ( \frac{-12}{2}, \frac{14}{2} )=(-6,7)

Therefore, the coordinate of point M is, (-6,7).

7 0
2 years ago
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