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Hitman42 [59]
2 years ago
5

What is the scale factor of AABC to A DEF?

Mathematics
1 answer:
Tasya [4]2 years ago
5 0

Answer: D

Step-by-step explanation:

the scale factor is 6

Triangle ABC  has the lengths  4,2,4   and DEF has the lengths 24,12,24

so for the triangle ABC's lengths to become triangle DEF  is is supposed to be multiplied by 6

4*6= 24

2*6= 12

4*6= 24

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Lilly is a pizza driver. Lilly has to make 4 deliveries.
Veronika [31]

Answer:

23 min 30 sec

Step-by-step explanation:

First, you add 35 + 14 + 18 + 27 which is 94.
Next, you divide 94 by the number of deliveries there were. Which is 4.
94/4 = 23.5.
So your answer would be 23 minutes and 30 seconds.

I Hope This Helped :D

5 0
1 year ago
Read 2 more answers
Find the common denominator 2/7 and 7/10
deff fn [24]

Answer:

70

Step-by-step explanation:

Finding the common denominator is really just finding the gcf of 7 and 10. The gcf of 7 and 10 is 70. So the common denominator is 70.

5 0
3 years ago
If x+9.8=14.7, what is the value of 8(x-3.7?
yulyashka [42]
First find X by subtracting 9.8 from 14.7
X should equal 4.9
than fill in the equation for x
8(4.9-3.7)
you then subtract in the parenthasis
getting the answer of 1.2
finally multiply 1.2x8
Your final answer is 9.6
3 0
3 years ago
Find the distance from the point (1,4) to the line y = 1/3x - 3
Troyanec [42]

Answer:

Step-by-step explanation:

If I'm not mistaken, and I very well could be, this is a calculus problem(?). In order to find the distance without calculus you'd need a point on the given line to use to find the distance in the distance formula. But you don't have a point on the given line, so we can find the shortest distance between the point (1, 4) and the given line using the derivative of the polynomial formed when using the distance formula.

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2} and we have the x and y for x2 (or x1...it doesn't matter which you choose to fill in):

d=\sqrt{(1-x)^2+(4-y)^2}

but what we find is that we have too many unknowns here, namely, the distance, the x coordinate, and the y coordinate. So we can replace the y coordinate with what y is equal to in terms of the linear equation:

d=\sqrt{(1-x)^2+(4-\frac{1}{3}x-3)^2 } and simplify:

d=\sqrt{(1-x)^2+(7-\frac{1}{3}x)^2 }

. No we'll expand each binomial by squaring:

d=\sqrt{(1-2x+x^2)+(49-\frac{14}{3}x+\frac{1}{9}x^2)  }

.  Combining like terms gives us

d=\sqrt{\frac{10}{9}x^2-\frac{20}{3}x+50  }

The distance between the point (1, 4) and the given line will be at a minimum when the polynomial above is at a minimum. We find the value of x for which the polynomial is at a minimum by finding its derivative, setting the derivative equal to 0, and then solving for x. The derivative of the polynomial is

\frac{20}{9}x-\frac{20}{3}

Setting equal to 0 and getting rid of the denominators gives us

20x - 60 = 0

Solving for x gives us

20x = 60 and x = 3.

That's the value of x that gives us the shortest distance between (1, 4) and the line y = 1/3x - 3. Sub into the distance formula that x value to find the distance:

d=\sqrt{(\frac{10}{9})(3)^2-(\frac{20}{3})(3)+50   }

which simplifies down, finally, to

x ≈ 6.325 units

8 0
3 years ago
What is the value of x <br><br> A. 20<br> B. 34<br> C. 60<br> D. 69
Grace [21]

Answer:

A

Step-by-step explanation:

The given angles are vertical and thus congruent, so

3x = x + 40 ( subtract x from both sides )

2x = 40 ( divide both sides by 2 )

x = 20 → A

4 0
3 years ago
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