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Vanyuwa [196]
2 years ago
7

What is the principal, if the interest earned is $22, the simple annual interest rate is 2%, and the time is one year?

Mathematics
1 answer:
seropon [69]2 years ago
4 0

Answer:

$1,100

Step-by-step explanation:

first find the principal first Multiply the rate 0.02 by the time 1 year this gives us 0.02 then divide the interest ($22) by 0.02 then you get $1,100.

Hope that helped!

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What is the surface area of the triangular prism?<br> pls help!!
Liono4ka [1.6K]

Answer:

168

Step-by-step explanation:

3 0
3 years ago
Trees planted by a landscaping firm have a 90% one-year survival rate, If they plant 16 trees in a park, what is the following p
irina1246 [14]

Answer:

Pr(all will survive in one year) = 0.35 to 2 decimal places

Pr(at least 8 will survive) = 0.39 to 2 decimal places.

Step-by-step explanation:

Probability of a tree surviving one year is 0.9. While not surviving probability is 1 - 0.9 = 0.1

This is obtained from the 90℅ surviving rate for one year planted by the landscaping firm.

Probability that if 10 trees are planted, all will survive for one year is:

0.9x0.9x0.9x0.9x0.9x0.9x0.9x0.9x0.9x0.9 = 0.9^10 = 0.349

Probability that at least 8 will survive in one year can be expressed as

8 survived x 2 not survived +(or) 9 survived x 1 not survived +(or) 10 survived

= [(0.9^8)x(0.1^2) + (0.9^9)x(0.1^1) + (0.9^10)] = 0.391

Step-by-step explanation:

6 0
3 years ago
1.) Maggie has a collection of 1,200 Pennies. Of these, 25% are dated before 1980, 35% are dated from 1980-
Strike441 [17]

Answer:

rest of them (40%)

Step-by-step explanation:

4 0
3 years ago
All of the following have the same unit price except _____.
Aliun [14]
2 1/2 for $6.25 is the answer
5 0
3 years ago
Read 2 more answers
Help with 21 would be much appreciated.
umka2103 [35]

Answer:

\large\boxed{x=2\sqrt{21}\ and\ y=4\sqrt3}

Step-by-step explanation:

Look at the picture.

ΔADC and ΔCDB are similar. Therefore the sides are in proportion:

\dfrac{AD}{CD}=\dfrac{CD}{DB}

We have

AD=14-8=6\\CD=y\\DB=8

Substitute:

\dfrac{6}{y}=\dfrac{y}{8}         <em>cross multiply</em>

y^2=(6)(8)

y^2=48\to y=\sqrt{48}\\\\y=\sqrt{16\cdot3}\\\\y=\sqrt{16}\ cdot\sqrt3\\\\\boxed{y=4\sqrt3}

For x use the Pythagorean theorem:

x^2=6^2+(4\sqrt3)^2\\\\x^2=36+48\\\\x^2=84\to x=\sqrt{84}\\\\x=\sqrt{4\cdot21}\\\\x=\sqrt4\cdot\sqrt{21}\\\\\boxed{x=2\sqrt{21}}

3 0
3 years ago
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