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leva [86]
2 years ago
7

What's the answer to this?

Mathematics
1 answer:
morpeh [17]2 years ago
5 0
1: given 2: distributive property 3: multiplication property of equality 4: addition property of equality 5: division property of equality
You might be interested in
A certain type of chocolate bar is sold as follows.
Scrat [10]

Answer:

Step-by-step explanation:

You would never buy a 10-pack, because two 5-packs cost less.

To buy 3 bars you need a single bar and a pair of single bars for £0.82 + £0.82+ £0.41 = £2.05

To buy 30 bars you need 3 pairs of 5-bar packs = 3×£5.75 =  £17.25

To buy the remaining 5 bars you need one 5-bar pack = £3

cost = £2.05 + £17.25 + £3 = £22.30

5 0
3 years ago
Determine the utilization and the efficiency for each situations:A. A loan processing operation that processes an average of 7 l
Vera_Pavlovna [14]

Answer:

A) Utilization = 70%

Efficiency = 87.5%

B) Utilization = 66.67%

Efficiency = 80%

Step-by-step explanation:

Determine the utilization and the efficiency for each situations:

A. A loan processing operation that processes an average of 7 loans per day. The operation has a design capacity of 10 loans per day and an effective capacity of 8 loans per day.

Formula for Utilization = Actual Output /

Design Capacity × 100

Actual output = 7 loans per day

Design capacity = 10 loans per day

Utilization = 7/10 × 100

= 70%

Efficiency = Actual output / Effective capacity × 100

Actual output = 7 loans per day

Effective capacity = 8 loans per day

Efficiency = 7/8 × 100

= 87.5%

B. A furnace repair team that services and average of four furnaces a day if the design capacity is six furnaces a day and the effective capacity is five furnaces a day.

Formula for Utilization = Actual Output /

Design Capacity × 100

Actual output = four furnaces a day

Design capacity = six furnaces a day

Utilization = 4/6 × 100

= 66.67%

Efficiency = Actual output / Effective capacity × 100

Actual output = four furnaces a day

Effective capacity = five furnaces a day

Efficiency = 4/5 × 100

= 80%

6 0
3 years ago
5) In a certain supermarket, a sample of 60 customers who used a self-service checkout lane averaged 5.2 minutes of checkout tim
Ne4ueva [31]

Answer:

\S^2_p =\frac{(60-1)(3.1)^2 +(72 -1)(2.8)^2}{60 +72 -2}=8.643

S_p=2.940

t=\frac{(5.2 -6.1)-(0)}{2.940\sqrt{\frac{1}{60}+\frac{1}{72}}}=-1.751

df=60+72-2=130

p_v =P(t_{130}

Assuming a significance level of \alpha=0.05 we have that the p value is lower than this significance level so then we can conclude that the mean for checkout time is significantly less for people who use the self-service lane

Step-by-step explanation:

Data given

Our notation on this case :

n_1 =60 represent the sample size for people who used a self service

n_2 =72 represent the sample size for people who used a cashier

\bar X_1 =5.2 represent the sample mean for people who used a self service

\bar X_2 =6.1 represent the sample mean people who used a cashier

s_1=3.1 represent the sample standard deviation for people who used a self service

s_2=2.8 represent the sample standard deviation for people who used a cashier

Assumptions

When we have two independent samples from two normal distributions with equal variances we are assuming that  

\sigma^2_1 =\sigma^2_2 =\sigma^2

The statistic is given by:

t=\frac{(\bar X_1 -\bar X_2)-(\mu_{1}-\mu_2)}{S_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2}}}

And t follows a t distribution with n_1+n_2 -2 degrees of freedom and the pooled variance S^2_p is given by this formula:

\S^2_p =\frac{(n_1-1)S^2_1 +(n_2 -1)S^2_2}{n_1 +n_2 -2}

System of hypothesis

Null hypothesis: \mu_1 \geq \mu_2

Alternative hypothesis: \mu_1 < \mu_2

This system is equivalent to:

Null hypothesis: \mu_1 - \mu_2 \geq 0

Alternative hypothesis: \mu_1 -\mu_2 < 0

We can find the pooled variance:

\S^2_p =\frac{(60-1)(3.1)^2 +(72 -1)(2.8)^2}{60 +72 -2}=8.643

And the deviation would be just the square root of the variance:

S_p=2.940

The statistic is given by:

t=\frac{(5.2 -6.1)-(0)}{2.940\sqrt{\frac{1}{60}+\frac{1}{72}}}=-1.751

The degrees of freedom are given by:

df=60+72-2=130

And now we can calculate the p value with:

p_v =P(t_{130}

Assuming a significance level of \alpha=0.05 we have that the p value is lower than this significance level so then we can conclude that the mean for checkout time is significantly less for people who use the self-service lane

5 0
3 years ago
matt can buy an 8-ounce jar of salsa for $2.79 or a 15-ounce jar os salsa for $5.54. which jar has the best unit rate?
oee [108]
8/2.79 = 1/2.867, or $2.86 per each oz
15/5.54 = 2.707/1, or 2 oz for every 1 dollar

the 15 oz jar of salsa has the better unit rate

hope this helps
7 0
3 years ago
Suppose you do an analysis of the starting salaries of 100 recent Lehman graduates. You find that the average starting salary is
madreJ [45]

Answer:

a) (59180,60820)

b) (59020,60980)        

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = $60,000

Standard Deviation, σ = $5,000

Sample size, n = 100

a) 90% critical values

\mu \pm z_{critical}\frac{\sigma}{\sqrt{n}}

Putting the values, we get,

z_{critical}\text{ at}~\alpha_{0.10} = 1.64

60000 \pm 1.64(\frac{5000}{\sqrt{100}} ) = 60000 \pm 820 = (59180,60820)

b) 95% critical values

\mu \pm z_{critical}\frac{\sigma}{\sqrt{n}}

Putting the values, we get,

z_{critical}\text{ at}~\alpha_{0.05} = 1.96

60000 \pm 1.96(\frac{5000}{\sqrt{100}} ) = 60000 \pm 980= (59020,60980)

5 0
3 years ago
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