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Elis [28]
3 years ago
7

The following method is intended to return true if and only if the parameter val is a multiple of 4 but is not a multiple of 100

unless it is also a multiple of 400. The method does not always work correctly public boolean isLeapYear(int val) if ((val 4) == 0) return true; else return (val & 400) == 0; Which of the following method calls will return an incorrect response?
A .isLeapYear (1900)
B. isLeapYear (1984)
C. isLeapYear (2000)
D. isLeapYear (2001)
E. isLeapYear (2010)
Computers and Technology
1 answer:
Tresset [83]3 years ago
5 0

Answer:

.isLeapYear (1900) will return an incorrect response

Explanation:

Given

The above method

Required

Which method call will give an incorrect response

(a) will return an incorrect response because 1900 is not a leap year.

When a year is divisible by 4, there are further checks to do before such year can be confirmed to be a leap year or not.

Since the method only checks for divisibility of 4, then it will return an incorrect response for years (e.g. 1900) that will pass the first check but will eventually fail further checks.

<em>Hence, (a) answers the question;</em>

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We informally define the term corresponding element as follows: The first element in an array and the last element of the array
yanalaym [24]

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For element, arr[0], the corresponding element is arr[10-1-0] = arr[9].

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The number of elements that an array can hold is one more than the index of the last element of the array.

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#include <iostream>

using namespace std;

int main() {    

   int len=10, arr[len],k;    

   for(k=0; k<len; k++)

   {

       // elements are initialized to twice their index

       arr[k] = k*2;

   }

   cout<<"Element "<<" Index "<<"\t"<<" Corresponding "<<" Index"<<endl;

   for(k=0; k<len/2; k++)

   {

       cout<<arr[k]<<"\t"<<"\t"<<"\t"<<k<<"\t"<<"\t"<<"\t"<<arr[len-1-k]<<"\t"<<"\t"<<len-1-k<<endl;

   }

}

OUTPUT

Element Index    Corresponding   Index

0  0   18  9

2  1   16  8

4  2   14  7

6  3   12  6

8  4   10  5

 

The above program initializes all the elements of the array to twice the value of their corresponding index. Following this, the element, its index, the corresponding element and its index is displayed.

All the above is achieved using for loop. The size of the array and its elements can be changed.

The expression for the corresponding element is thus explained.

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