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3 years ago

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The perimeter of a rectangle is 98 m. The length of the rectangle is 9 m more than four times the width. Find the dimensions of

the rectangle.

1 answer:

Olenka [21]3 years ago

3 0

P=98 m

l +9=4w

p=2l+2w

98=2(4w-9) +2w

98 = 8w-18+2w

116=10w

w=11,6 m

l = 4w-9 = 4*11,6 -9 = 46,4 -9 = 37,4 m

w=11,6 m
l= 37,4 m

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Part B if the height of each prism is 10 Cm what is the surface area prism

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Answer:

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Prism B:

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Step-by-step explanation:

Given

See attachment for prisms

$Height(h) = 10cm$

Required

Determine the surface area of both prisms

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Where

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and

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From the attachment;

$a = 8; b =6; c =10$

So, we have:

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$s = \frac{8 + 6 + 10}{2}$

$s = \frac{24}{2}$

$s = 12$

Also:

$A_b = \sqrt{s * (s - a) * (s -b) * (s - c)}$

$A_b = \sqrt{12 * (12 - 8) * (12 - 6) * (12 - 10)}$

$A_b = \sqrt{576}$

$A_b = 24$

So:

$Area = 2 * A_b + (a + b + c) * h$

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Prism B is a rectangular prism. So, the area is calculated as:

$Area = 2 * (ab + bh + ah)$

From the attachment

$a = b = 5$

$h =10$

So:

$Area =2 * (5 * 5 + 5 * 10 + 5 * 10)$

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