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Sauron [17]
3 years ago
8

Give example for each statement

Mathematics
1 answer:
Arlecino [84]3 years ago
7 0
2+2=4
3.54 times 2 is 7.08
3.5 times 3.5 is 7
:)
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Help asap!!!!!! answer 4 5 and 6 please thx TvT
Yuliya22 [10]

Answer:

4. 9

5. 4

6. 35

Step-by-step explanation:

7 0
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Need a correct answer please
zloy xaker [14]

Answer       x=14         y=1

Step-by-step explanation:

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2 years ago
What is 0.8 of 1,046
dmitriy555 [2]

Answer:

Concept: Mathematical Computation

  1. You want to know what 80% of 1046 is
  2. Hence you do 1046 × 0.80
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4 0
2 years ago
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Choose 5 cards from a full deck of 52 cards with 13values (2, 3, 4, 5, 6, 7, 8, 9, 10, J, Q, K, A) and 4 kinds(spade, diamond, h
Delvig [45]

Answer:

a) 182 possible ways.

b) 5148 possible ways.

c) 1378 possible ways.

d) 2899 possible ways.

Step-by-step explanation:

The order in which the cards are chosen is not important, which means that we use the combinations formula to solve this question.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

In this question, we have that:

There are 52 total cards, of which:

13 are spades.

13 are diamonds.

13 are hearts.

13 are clubs.

(a)Two-pairs: Two pairs plus another card of a different value, for example:

2 pairs of 2 from sets os 13.

1 other card, from a set of 26(whichever two cards were not chosen above). So

T = 2C_{13,2} + C_{26,1} = 2*\frac{13!}{2!11!} + \frac{26!}{1!25!} = 182

So 182 possible ways.

(b)Flush: five cards of the same suit but different values, for example:

4 combinations of 5 from a set of 13(can be all spades, all diamonds, and hearts or all clubs). So

T = 4*C_{13,5} = 4*\frac{13!}{5!8!} = 5148

So 5148 possible ways.

(c)Full house: A three of a kind and a pair, for example:

4 combinations of 3 from a set of 13(three of a kind ,c an be all possible kinds).

3 combinations of 2 from a set of 13(the pair, cant be the kind chosen for the trio, so 3 combinations). So

T = 4*C_{13,3} + 3*C_{13.2} = 4*\frac{13!}{3!10!} + 3*\frac{13!}{2!11!} = 1378

So 1378 possible ways.

(d)Four of a kind: Four cards of the same value, for example:

4 combinations of 4 from a set of 13(four of a kind, can be all spades, all diamonds, and hearts or all clubs).

1 from the remaining 39(do not involve the kind chosen above). So

T = 4*C_{13,4} + C_{39,1} = 4*\frac{13!}{4!9!} + \frac{39!}{1!38!} = 2899

So 2899 possible ways.

4 0
3 years ago
Please help could you explain or show work so I will remember how to do problems like this?
antiseptic1488 [7]

Answer:

x = -8

Step-by-step explanation:

4x - (x - 4) = - 20

Distribute the minus sign

4x - x +4 = -20

Combine like terms

3x+4 = -20

Subtract 4 from each side

3x+4-4 = -20-4

3x = -24

Divide by 3

3x/3 = -24/3

x = -8

3 0
2 years ago
Read 2 more answers
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