Answer:
8 and 16 are not equal to 24
We can solve it like:
3x^3+3x^2+x+1= (3x^3+3x^2)+(x+1)=
3x^2(x+1)+(x+1)=
= (x+1)(3x^2+1)
Have a good day
The given quadratic equation will not have any real solution for c<-9/4.
The given quadratic equation is:
<h3>What is a quadratic equation?</h3>
Any equation of the form 
is called a quadratic equation with a≠0.
In order to have no real solution, the discriminant of a quadratic equation will be less than zero.
For the given quadratic equation will have no real solutions.
Hence, the given quadratic equation will not have any real solution for c<-9/4.
To get more about quadratic equations visit:
brainly.com/question/1214333
Answer:
y = -2·x^2 - 5·x - 18
y = -2·(x^2 + 10·x + 36)
y = -2·(x^2 + 10·x + 36)
y = -2·(x - (-5 - √11·i))·(x - (-5 + √11·i))
Maybe there is a typo in the original question, because there is no factorisation in the real numbers.
Because the question is " find the minimum value of y" the coefficient before x^2 must be a positive number. so it could be
y = 2·x^2 - 5·x - 18
Can you check this out?
Answer:
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