Question

What is the area of sector with a central angle of 160 and a diameter of 5.8 m? Round the answer to the nearest tenth.

Answer 1

Answer:

$A=11.7\ m^2$

Step-by-step explanation:

Given that,

Central angle, $\theta=160^{\circ}$

Diameter,d = 5.8 m

Radius, r = 2.9 m

We need to find the area of sector. The formula for the area of sector is given by :

$A=\dfrac{\theta}{360}\times \pi r^2\\\\=\dfrac{160}{360}\times 3.14\times 2.9^2\\\\=11.7\ m^2$

So, the area of a sector is equal to $11.7\ m^2$.