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viva [34]
3 years ago
6

7/15(x+4)+2/15(x+4)=7 1/5

Mathematics
2 answers:
torisob [31]3 years ago
8 0

Answer:

x = 59/3

Step-by-step explanation:

34kurt3 years ago
7 0
X=59/3
Download the app photo math and it will help
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In an insect colony there are 270 insects after 9 days. If there were initially 80 insects how long will it take the population
Semenov [28]

Answer:

The time it will take the population to grow to 800 insects is 17 days.

Step-by-step explanation:

The growth function of the insects is exponential.

The exponential growth function is:

y=a(1+r)^{t}

Here,

<em>y</em> = final value

<em>a</em> = initial value

<em>r</em> = growth rate

<em>t</em> = time taken

It is provided that there were 270 insects after 9 days and initially there were 80 insects.

Compute the value of <em>r</em> as follows:

y=a(1+r)^{t}\\\\270=80(1+r)^{9}\\\\3.375=(1+r)^{9}\\\\\ln(3.375)=9\cdot \ln(1+r)\\\\0.135155=\ln(1+r)\\\\1+r=1.14471\\\\r=0.145

Now, compute the time it will take the population to grow to 800 insects as follows:

800=80(1+0.145)^{t}\\\\10=(1.145)^{t}\\\\\ln(10)=t\cdot \ln(1.145)\\\\t=17.00522\\\\t\approx 17

Thus, the time it will take the population to grow to 800 insects is 17 days.

7 0
3 years ago
Upper bound and lower bound of 17
Licemer1 [7]

Answer:

Step-by-step explanation:

Hey there this si the upper and lower bound for 17

16.5<17<17.5

8 0
3 years ago
Find the inequality represented by the graph
xeze [42]

Answer:

88

Step-by-step explanation:

3 0
3 years ago
Where is the point (-2 -3) located in the coordinate plane
labwork [276]

Answer:

It's located in the third quadrant

(X,Y)

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
A ball is thrown into the air from an apartment balcony and falls to the ground. The height of the ball, h metres, t seconds aft
andriy [413]

Answer:

1+2\sqrt{2} seconds

Step-by-step explanation:

When the ball hits the ground, its height will obviously be 0. Therefore, you can set up the equation the following way:

0=-5t^2+10t+35 \\\\-5(t^2-2t-7)=0

Plugging this into the quadratic equation, you get:

t=\dfrac{2\pm\sqrt{4+28}}{2}= \\\\\dfrac{2\pm4\sqrt{2}}{2}= \\\\1\pm2\sqrt{2}

Since the time must be positive, it takes the ball 1+2\sqrt{2} seconds to hit the ground, or around 3.828. Hope this helps!

7 0
3 years ago
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