I think you can solve it by
=(x^2 - y^2) *( x^2 + y^2)
= (x -y)*(x+y)*(x^2 + y^2)
( 4 / 5 )^-2 = ( 5 / 4 )^2 = 25 / 16 ;
Answer:
The equation would be y = 4/3x - 3
3y - 1 = 28
+ 1 + 1
----------------
3y = 29
---- ----
3 3
y= 9.66
The probability that the sample proportion is within ± 0.02 of the population proportion is 0.3328
<h3>How to determine the probability?</h3>
The given parameters are:
- Sample size, n = 100
- Population proportion, p = 82%
Start by calculating the mean:



Calculate the standard deviation:



Within ± 0.02 of the population proportion are:


Calculate the z-scores at these points using:

So, we have:


The probability is then represented as:
P(x ± 0.02) = P(-0.43 < z < 0.43)
Using the z table of probabilities, we have:
P(x ± 0.02) = 0.3328
Hence, the probability that the sample proportion is within ± 0.02 of the population proportion is 0.3328
Read more about probability at:
brainly.com/question/25870256
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