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andrew11 [14]
4 years ago
5

A = ?, b = 48, c = 57

Mathematics
1 answer:
Sergio [31]4 years ago
8 0

Answer:

a= 9

Step-by-step explanation:

If you are using the forumla a+b=c

a+48=57

57-48=9

a=9

9=48=58

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Find the value of c that makes x^2–6x + c a perfect square trinomial and write as a binomial squared.
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Answer: 9

Step-by-step explanation:

Given

The function is x^2-6x+c

To make it a perfect square, compare it with (a-b)^2=a^2+b^2-2ab

Here,

x=a,\\-6x=-2ab\\\\\therefore b=3

So, c must be square of b i.e. 9

x^2-6x+c\Rightarrow x^2-6x+9\\\Rightarrow (x-3)^2

Therefore, value of c is 9.

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Answer/Step-by-step explanation:

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3 years ago
The image of a triangle after it has been dilated with a center at the origin has vertices at A’(-12,6) B’(6,-18) and C’ if the
ArbitrLikvidat [17]

Answer:

  • scale factor is 2/3.
  • coordinates of B are (9,-27).
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Step-by-step explanation:

The image of a triangle after it has been dilated with a center at the origin has vertices at A’(-12,6) B’(6,-18) and C’ .

Point A has coordinates of (-18,9) and the pre- image of C' point C has coordinates of (18,12).

Clearly when we compare point A and point A' we see that the transformation is a dilation.

let the scale factor of dilation is 'k'.

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i.e. k(-18,9)=(-12,6)

(-18k,9k)=(-12,6)

i.e. -18k=-12

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Hence, on solving we get:

k=2/3

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we find the coordinates of B(c,d) by:

2/3(c,d)=(6,-18)  since B→ B'

2/3×c=6

Hence c=9

and 2/3 ×d=-18

d=-27.

Hence, the coordinates of B are (9,-27).

Also the coordinates of C are (18,12)

Hence, coordinates of C' are:

(\dfrac{2}{3}\times 18,\dfrac{3}{2}\times 12)\\\\=(12,18)

Hence, the coordinates of C' are : (12,18)

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