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3 years ago

Write the mixed number as a decimal. 681/5

Mathematics

2 answers:

irga5000 [103]3 years ago

5 0

I think you'd divide 681/5 and i got 136.2 for that so

nekit [7.7K]3 years ago

3 0

Answer:

136.2

Step-by-step explanation:

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Determine the equation of the line given by the graph.

Zolol [24]

Answer:

We can tell by the graph that it has a positive slope. The

y-intercept is at positive 4. Trying to find the next whole number intercept point will be at (-2,0). Count up and over from that point to the y-intercept point, and put it in rise over run form... 5/2 (up 5, over 2). Now apply these known variables into the slope intercept form: y = mx + b.

The final answer is: y = (5/2)x + 5

M is the slope and B is the y-intercept.

3 0

3 years ago

Simplify each expression then factor the expression 14-28t-5(7+10t)

ludmilkaskok [199]

Answer:

Simplified: -21-98t

Factored: -7(14t+3)

Step-by-step explanation:

The given expresion is:

14-28t-5(7+10t)

We expand the parenthesis to get:

$14 - 28t -35 - 70t$

We group like terms to get:

$14 -35 - 28t- 70t$

We combine similar terms to get:

$- 21- 98t$

We now factor to obtain:

$- 21- 98t = - 7(14t + 3)$

5 0

4 years ago

Describe two methods that can be used to find the area of the composite figure.

vekshin1

You can draw a line to make a square and a rectangle to help find the area. The other method would be to form 2 squares and 1 rectangle.

This is probably wrong but I hope it helps!

4 0

3 years ago

Read 2 more answers

What number has 9 thousands and 4 less hundreds than thens

Reil [10]

..........9500..........

6 0

4 years ago

A student wants to survey the sophomore class of 200 students about whether the school should require uniforms. A

Fittoniya [83]

Answer: C

Step-by-step explanation:

<u>Given:</u>

Sample size (n) = 50

x = 12

$\widehat{\mathbf{p}}=\frac{\mathbf{x}}{n}=\frac{12}{50}=0.24$

Confidence level = 90%

α = 1 − 0.90 = 0.10

α/2 = 0.05

$\text { Critical value }\left(z_{c}\right)=z_{\frac{\alpha}{2}}=z_{0.05}=1.6449$

(from standard normal table)

90% Confidence interval is,

$\begin{aligned}&\text { Confidence interval }=\widehat{\mathbf{p}} \pm z_{c} \times \sqrt{\frac{\hat{\mathbf{p}}(1-\hat{\mathbf{p}})}{n}} \\&\text { C. I }=0.24 \pm 1.6449 \times \sqrt{\frac{0.24(1-0.24)}{50}} \\&\text { C. I }=0.24 \pm 1.65 \times \sqrt{\frac{0.24(1-0.24)}{50}}\left\end{aligned}$

Therefore, 90% confidence interval for the true proportion of sophomores who favour the adoption of uniforms is C

6 0

3 years ago