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i hope this is the answer im glad to help
Answer:
im not the best at algebra but
2a+3b+4c
Step-by-step explanation:
subtract
(2a−3b+4c) from the sum of (a+3b−4c),(4a−b+9c) and (−2b+3c−a).
add
=(a+3b−4c)+(4a−b+9c)+(−2b+3c−a)
=(a+4a−a)+(3b−b−2b)+(−4c+9c+3c)
=4a+8c
then subtract
=(4a+8c)−(2a−3b+4c)
=4a+8c−2a+3b−4c
=2a+3b+4c
Soo first apply the exponent rule (2^5)^1/3*1/4
1/3*1/4= 1/12
so (2^5)^1/12
then you apply the exponent rule again 2^5*1/2
so 5*1/12= 5/12
So the answer would be 2^5/12
Answer:
(-1, 19) and (3, -81)
Step-by-step explanation:
f(x) = 2x³ − 6x² − 27x
f'(x) = 6x² − 12x − 27
-9 = 6x² − 12x − 27
0 = 6x² − 12x − 18
0 = x² − 2x − 3
0 = (x + 1) (x − 3)
x = -1 or 3
f(-1) = 19
f(3) = -81
The points are (-1, 19) and (3, -81).
