I think the correct answer would be B. Octane is a component of fuel used in internal combustion engines. the dominant intermolecular forces in octane are london dispersion forces. Dipole-dipole bonds happens only with polar substances. Hydrogen bonding occurs when H bonds with an O, F or N atom. Covalent bonds are not intermolecular force rather it is an intramolecular force. Carbon-Hydrogen bonds, as far as I know, are not a type of bond, intermolecular or intramolecular. So, we are left with london dispersion force. It is a temporary force that happens when electrons of two atoms in adjacent would occupy positions that would form dipoles temporarily.
Answer:
4NH₃ + 5O₂ → 4NO + 6H₂O ΔH = -904 kj
Explanation:
Given data:
Energy evolved when one mole of NH₃ react = 226 kj
Energy evolved when 4 mole of NH₃ react = ?
Solution:
Chemical equation:
4NH₃ + 5O₂ → 4NO + 6H₂O
It is stated in question that when one mole of ammonia react 226 kj energy evolved.
When 4 moles react energy evolved is,
1 mol = -226 kj
4 mol × -226 kj / 1mol
-904 kj
when 4 moles of ammonia react 904 kj energy is evolved.
Complete thermal equation:
4NH₃ + 5O₂ → 4NO + 6H₂O ΔH = -904 kj
Answer:
(a) CH₃CH₂CH₂CH₂CH₂OH
(b) CH₃OH
(c) CH₃CH₂CH₂CH₂CH₂OH
Explanation:
In alcohols, the -OH group is responsible for the polarity. The longer the non-polar hydrocarbon chain, the less polar is the compound.
Regarding solubility, we will consider the general rule "like dissolves like", meaning polar is soluble in polar and non-polar is soluble in non-polar.
(a) I₂ is non-polar, so it will be more soluble in the least polar solvent, which is pentanol (CH₃CH₂CH₂CH₂CH₂OH).
(b) NaCl is an ionic compound, that is, there is a big difference in electronegativity between the atoms. Then, it will be soluble in the most polar alcohol, methanol (CH₃OH).
(c) Pentane (CH₃CH₂CH₂CH₂CH₃) is non-polar, so it will be more soluble in the least polar solvent, which is pentanol (CH₃CH₂CH₂CH₂CH₂OH).
Answer:
Answer: A. 3 mol 3 mol Al:
Explanation:
Te given balanced chemical equation is :
According to the stochiometry :
A: 3 mol 3 mol Al:
3 moles of chlorine reacts with 2 moles of aluminium
B. 2 mol 3 mol :
2 moles of aluminium reacts with 3 moles of chlorine
C. 2 mol 2 mol Al
2 mol of aluminium produces 2 mol of
D. 3 mol 2 mol
3 moles of chlorine produces with 2 moles of
Thus the conversion factor not used for mole to mole calculations is 3 mol 3 mol Al:
Explanation: