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krok68 [10]
4 years ago
15

15

Chemistry
1 answer:
balu736 [363]4 years ago
7 0

Answer:

Attractions between molecules cause a reduction in volume

Explanation:

This is a very important concept of the ideal gas law application. The ideal gas law applies when several conditions are met:

  • the size of individual atoms or molecules should be negligible, so that we may assume that the volume of the gas is equal to the volume of a container;
  • the attractions between individual atoms should also be negligible, so that on average the gas fills the whole container and the volume of a container would be equal to the volume of the gas.

Therefore, the ideal gas law applies best in scenarios where we have a high temperature and a low pressure (or large volume). The larger the volume gets, the more negligible is the size of a molecule compared to the size of a container.

Speaking of temperature, the greater the temperature, the higher the kinetic energy of the gas molecules, so that the average distances between them increase and the attraction forces are minimized.

However, having a low temperature would cause the molecules of a gas move slower and attraction forces would be more significant due to lower average distances between the molecules.

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(a) calculate the %ic of the interatomic bond for the intermetallic compound tial3. (b) on the basis of this result, what type o
Mrrafil [7]

Answer :

The correct answer is  %IC = 10 % and bond is  covalent  bond with slight polarity.

<u>Percent Ionic Character :</u>

It is defined as percent of ionic character present in a  polar covalent bond . The formula   of % ionic character (%IC) is given as follows :

Percent Ionic character = 1 - e^-^0^.^2^5 ^*^(^X^a^-^X^b^) * 100

Where Xa = Electronegativity of A atom   and Xb = Electronegativity of B atom

Given : Molecule is TiAl₃

Electronegativity of Ti = 2.0

Electronegativity of Al = 1.6 ( From image shared )

Plug the value  in  above formula :

Percent Ionic character = 1 - e^-^0^.^2^5 ^*^(^2^.^0^-^1^.^6^) * 100

Percent Ionic character = 1 - e^(^-^0^.^2^5 ^*^0^.^4^) * 100

Percent Ionic character = 1 - e^(^-^0^.^1^) * 100

Value of e⁻¹ = 0.90

Percent ionic character = 1 - 0.90 * 100

Percent Ionic character = 10 %

<u>Since the % IC is 10 % , which is very less comparatively , hence the bond is covalent and  very less polar .</u>

8 0
3 years ago
What are the physical properties of chlorine?<br>​
Sonbull [250]

Answer:

The Physical Properties of Chlorine are as follows:

Color: Greenish-yellow.

Phase: Gas.

Odor: Disagreeable, suffocating smell.

Density: About two and one-half times as dense as air.

Solubility: Is soluble in water. ...

Boiling Point: The boiling point of chlorine is –34.05°C.

Melting Point: The melting point is –101°C.

Explanation:

Please mark me as the brainliest answer and please follow me for more answers

7 0
3 years ago
What is the limiting reactant if 12 moles of p4 react with 15 moles of o2?.
brilliants [131]

Answer:

see explanation

Explanation:

To determine limiting reactant divide mole quantities of reactants by the respective coefficient in the balanced equation. The smaller value is the limiting reactant.

    P₄      +     5O₂       => 2P₂O₅

12/1 = 12      15/5 = 3

O₂ is the limiting reactant. P₄ will be in excess when rxn stops.

4 0
2 years ago
24g copper is submerged in water in a graduated cylinder, the total volume increases bu 2.7ml what is the density of copper
Brilliant_brown [7]

Answer:

<h2>8.89 g/mL</h2>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume} \\

From the question we have

density =  \frac{24}{2.7}  \\  = 8.88888...

We have the final answer as

<h3>8.89 g/mL</h3>

Hope this helps you

8 0
3 years ago
Cu + 2AgNO3 → Cu(NO3)2 + 2Ag
Eva8 [605]

Answer:

m_{Ag}=135.8gAg

Y=88.4\%

Explanation:

Hello there!

In this case, according to the described chemical reaction, it is possible to compute the theoretical mass of silver as mass via the 1:2 mole ratio of copper to silver and their atomic mass in the periodic table, in order to perform the following stoichiometric setup:

m_{Ag}=40.gCu*\frac{1molCu}{63.55gCu}*\frac{2molAg}{1molCu}*\frac{107.87gAg}{1molAg}\\\\   m_{Ag}=135.8gAg

Next, given the actual yield of 120 g, we compute the percent yield via:

Y=\frac{120g}{135.8g}*100\%\\\\Y=88.4\%

Regards!

4 0
3 years ago
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