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krok68 [10]
4 years ago
15

15

Chemistry
1 answer:
balu736 [363]4 years ago
7 0

Answer:

Attractions between molecules cause a reduction in volume

Explanation:

This is a very important concept of the ideal gas law application. The ideal gas law applies when several conditions are met:

  • the size of individual atoms or molecules should be negligible, so that we may assume that the volume of the gas is equal to the volume of a container;
  • the attractions between individual atoms should also be negligible, so that on average the gas fills the whole container and the volume of a container would be equal to the volume of the gas.

Therefore, the ideal gas law applies best in scenarios where we have a high temperature and a low pressure (or large volume). The larger the volume gets, the more negligible is the size of a molecule compared to the size of a container.

Speaking of temperature, the greater the temperature, the higher the kinetic energy of the gas molecules, so that the average distances between them increase and the attraction forces are minimized.

However, having a low temperature would cause the molecules of a gas move slower and attraction forces would be more significant due to lower average distances between the molecules.

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An acetic acid buffer solution is required to have a pH of 5.27. You have a solution that contains 0.010 mol of Acetic acid. Wha
dlinn [17]

Answer:

Molarity of sodium acetate you will need to add is 0.0324M

Explanation:

<em>Assuming volume of the buffer is 1L.</em>

<em />

The pH of a buffer can be determined using Henderson-Hasselbalch equation:

pH = pKa + log [A⁻] / [HA]

<em>Where pKa is pKa of the weak acid,  [A⁻] molar concentration of conjugate base and [HA] molar concentration of weak acid</em>

<em />

Replacing for the acetic buffer (pKa = 4.76):

pH = 4.76 + log [Sodium Acetate] / [Acetic Acid]

As you have 0.010 moles of acetic acid in 1L:

[Acetic Acid] = 0.010mol / 1L = 0.010M

And you require a pH of 5.27:

5.27 = 4.76 + log [Sodium Acetate] / [0.010M]

0.51 = log [Sodium Acetate] / [0.010M]

10^0.51 = [Sodium Acetate] / [0.010M]

3.236 =  [Sodium Acetate] / [0.010M]

3.236 [0.010M] = [Sodium Acetate]

0.0324M = [Sodium Acetate]

<h3>Molarity of sodium acetate you will need to add is 0.0324M</h3>

<em />

7 0
3 years ago
The formula for binary ionic compound formed between cesium and fluorine
OleMash [197]

Answer:

Cesium fluoride(CsF)

Explanation:

A binary compound is a compound that is composed of 2 distinct element. An ionic compound is composed of ions, usually one is a metal why the other is a non metal. One element gives out electron to form cation and the other receives electron to form anion in a binary compound.

Cesium is a group 1 element and it has one valence electron and it can easily donate this 1 electron to form a bond with other element. Group 1 element are generally very reactive. Cesium is a metal

Fluorine is in  group 7 of the periodic table and is a non metal .Fluorine have 7 valency electron and requires  1 electron to form a stable octet.

When cesium and fluorine bond to form a binary compound cesium donate 1 electron and fluorine receives the 1 electron for both element to form a stable octet. The formula for the binary ionic compound of cesium and fluorine can therefore be expressed as Cesium fluoride(CsF)

7 0
3 years ago
Which is an alkaline earth metal?
Hitman42 [59]

Answer:

actually there are 6 of them

Explanation:

heres the list:

They are beryllium, magnesium, calcium, strontium, barium, and radium.

hope it helpssss :)

7 0
3 years ago
Read 2 more answers
What is the relatioship between atomic numbers and ionic radii of the elements in Group 1? what is the relationship between atom
Sever21 [200]
As atomic number increases atomic radii also increase down group 1. ionisation energy down group 1 will also decrease because as atomic radii gets bigger there is less electrostatic force between nuclei and electrons so less energy needed to remove valence electron.
6 0
3 years ago
How many grams of fluorine are contained in 8 molecules of boron trifluoride?
Lelu [443]
<h3>Answer:</h3>

             7.57 × 10⁻²² g of F

<h3>Solution:</h3>

Data Given:

                 Number of Molecules  =  8

                 M.Mass of BF₃ =  67.82 g.mol⁻¹

                 Mass of Fluorine atoms  =  ?

Step 1: Calculate Moles of BF₃

           Moles  =  Number of Molecules ÷ 6.022 × 10²³ Molecules.mol⁻¹

Putting value,

            Moles  =   8 Molecules ÷ 6.022 × 10²³ Molecules.mol⁻¹

            Moles  =  1.33 × 10⁻²³ mol

Step 2: Calculate Mass of BF₃:

                   Moles  =  Mass ÷ M.Mass

Solving for Mass,

                   Mass  =  Moles × M.Mass

Putting values,

                   Mass  =  1.33 × 10⁻²³ mol × 67.82 g.mol⁻¹

                   Mass  =  9.0 × 10⁻²² g

Step 3: Calculate Mass of Fluorine Atoms:

As,

                         67.82 g BF₃ contains  =  57 g of F

So,

                    9.0 × 10⁻²² g will contain  =  X g of F

Solving for X,

                       X =  (9.0 × 10⁻²² g × 57 g) ÷ 67.82 g

                        X  =  7.57 × 10⁻²² g of F

4 0
4 years ago
Read 2 more answers
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