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marissa [1.9K]
3 years ago
13

________ programs help solve the problem of running out of storage space by providing lists of application programs, stored vide

os, and other program files so that you can eliminate unused applications or archive large files elsewhere.
Computers and Technology
1 answer:
Leviafan [203]3 years ago
7 0

Answer:

Storage management

Explanation:

The programs that do this are known as Storage management programs. They are incredibly useful since they allow you to see which files are taking up the most amount of space as well as the importance that each file has on the system. Many of these programs have a different visual representation of the files such as pie charts or system blocks showing the percentage of space it is taking up. Everything in these programs is made to help the end-user visualize and analyze their data thoroughly.

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Write a program that prompts the user to enter an equation in the form of 10 5, or 10-5, or 1*5, or 13/4, or 13%4. The program s
grandymaker [24]

Answer:

  1. equation = input("Enter an equation: ")
  2. if("+" in equation):
  3.    operands = equation.split("+")
  4.    result = int(operands [0]) + int(operands[1])
  5.    print(operands[0] + "+" + operands[1] + "=" + str(result))
  6. elif("-" in equation):
  7.    operands = equation.split("-")
  8.    result= int(operands [0]) - int(operands[1])
  9.    print(operands[0] + "-" + operands[1] + "=" + str(result))  
  10. elif("*" in equation):
  11.    operands = equation.split("*")
  12.    result = int(operands [0]) * int(operands[1])
  13.    print(operands[0] + "*" + operands[1] + "=" + str(result))  
  14. elif("/" in equation):
  15.    operands = equation.split("/")
  16.    result = int(operands [0]) / int(operands[1])
  17.    print(operands[0] + "/" + operands[1] + "=" + str(result))  
  18. elif("%" in equation):
  19.    operands = equation.split("%")
  20.    result = int(operands [0]) % int(operands[1])
  21.    print(operands[0] + "%" + operands[1] + "=" + str(result))

Explanation:

The solution code is written in Python 3.

Firstly prompt user to enter an equation using input function (Line 1).

Create if-else if statements to check if operator "+", "-", "*", "/" and "%" exist in the input equation. If "+" is found (Line 3), use split method to get the individual operands from the equation by using "+" as separator (Line 5). Output the equation as required by the question using string concatenation method (Line 6).  The similar process is repeated for the rest of else if blocks (Line 7 - 22).  

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4 years ago
) Perform error checking for the data point entries. If any of the following errors occurs, output the appropriate error message
emmainna [20.7K]

Answer:

In Python:

entry = input("Sentence: ")

while True:

   if entry.count(",") == 0:

       print("Error: No comma in string")

       entry = input("Sentence: ")

   elif entry.count(",") > 1:

       print("Error: Too many comma in input")

       entry = input("Sentence: ")

   else:

       ind = entry.index(',')+1

       if entry[ind].isnumeric() == False:

           print("Comma not followed by an integer")

           entry = input("Sentence: ")

       else:

           break

print("Valid Input")

Explanation:

This prompts the user for a sentence

entry = input("Sentence: ")

The following loop is repeated until the user enters a valid entry

while True:

This is executed if the number of commas is 0

<em>    if entry.count(",") == 0:</em>

<em>        print("Error: No comma in string")</em>

<em>        entry = input("Sentence: ")</em>

This is executed if the number of commas is more than 1

<em>    elif entry.count(",") > 1:</em>

<em>        print("Error: Too many comma in input")</em>

<em>        entry = input("Sentence: ")</em>

This is executed if the number of commas is 1

   else:

This calculates the next index after the comma

       ind = entry.index(',')+1

This checks if the character after the comma is a number

       if entry[ind].isnumeric() == False:

If it is not a number, the print statement is executed

<em>            print("Comma not followed by an integer")</em>

<em>            entry = input("Sentence: ")</em>

If otherwise, the loop is exited

<em>        else:</em>

<em>            break</em>

This prints valid input, when the user enters a valid string

print("Valid Input")

Note that: entry = input("Sentence: ") <em>is used to get input</em>

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3 years ago
What does it mean to clear a setting in a dialog box?
yaroslaw [1]

Answer:

to delete it

Explanation:

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3 years ago
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