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marissa [1.9K]
3 years ago
13

________ programs help solve the problem of running out of storage space by providing lists of application programs, stored vide

os, and other program files so that you can eliminate unused applications or archive large files elsewhere.
Computers and Technology
1 answer:
Leviafan [203]3 years ago
7 0

Answer:

Storage management

Explanation:

The programs that do this are known as Storage management programs. They are incredibly useful since they allow you to see which files are taking up the most amount of space as well as the importance that each file has on the system. Many of these programs have a different visual representation of the files such as pie charts or system blocks showing the percentage of space it is taking up. Everything in these programs is made to help the end-user visualize and analyze their data thoroughly.

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Which technology is predominately used for contactless payment systems?
kompoz [17]
The correct answer for this question is this one: "a. wireless local area network (WLAN)."

<span>The technology that is predominately used for contactless payment systems is called the </span><u>wireless local area network (WLAN)</u><u />. It is even used now a days.
Hope this helps answer your question and have a nice day ahead.
7 0
3 years ago
While troubleshooting a network connection problem for a coworker, you discover the computer is querying a nonexistent DNS serve
tatuchka [14]

Answer:

nslookup ifconfig.

Explanation:

The nslookup is used a number of times by network admins to troubleshoot DNS related problems. In addition, this command finds IP addresses and name servers of hosts. This utility command queries the DNS database tables from every host in a network. It then determines the host name and issues an IP. It sort of converts your domain name into an IP addresses. This command combined with ifconfig finds the correct DNS servers and assigns the correct DNS server IP.

6 0
3 years ago
For what purposes do students collect data? Check all that apply.
Bumek [7]

Answer:

sounds like all of the above

Explanation:

only one im not 100% sure on is to examine a question's reliablity

5 0
3 years ago
Read 2 more answers
Write a program that accepts three decimal numbers as input and outputs their sum​
Sophie [7]

Answer:

sum = 0.0

for i in range(0,3):

   sum += float(input("Enter a decimal number to sum: "))

print ("Sum: ", sum)

*** Sample Input ***

Enter a decimal number to sum: 1.1

Enter a decimal number to sum: 2.2

Enter a decimal number to sum: 3.3

*** Sample Output ***

Sum:  6.6

Explanation:

For this problem, a method was devised in python to create the sum of three individual decimal numbers.

The first line of code, <em>sum = 0.0</em>, initializes a variable to the float type in which we will store the value of our sum.  Note, it is initialized to 0.0 to start from a value of 0 and be considered a float.

The second line of code, <em>for i in range(0,3):</em>  is the creation of a for loop control structure.  This will allow us to repeat a process 3 amount of times using the iterator i, from value 0 to 3 in this case.  Note, 0 is inclusive and 3 is exclusive in the python range.  This means the for loop will iterate with, i=0, i=1, and i=2.

The third line of code, <em>sum += float(input("Enter a decimal number to sum: "))</em>  is simply asking the user for a number, taking that input and converting it from a string into a float, and then summing the value with the previous value of sum and saving that into sum.

The fourth line of code, <em>print ("Sum: ", sum)</em> is simply displaying the final value that was calculated by adding the three user inputs together which were stored into the variable <em>sum</em>.

Cheers.

6 0
3 years ago
Read 2 more answers
Can you please make a simple python program? I will give you 20 points and branliest if it is good! It must include:
alekssr [168]

Answer:

# Solve the quadratic equation ax**2 + bx + c = 0

# import complex math module

import cmath

a = 1

b = 5

c = 6

# calculate the discriminant

d = (b**2) - (4*a*c)

# find two solutions

sol1 = (-b-cmath.sqrt(d))/(2*a)

sol2 = (-b+cmath.sqrt(d))/(2*a)

print('The solution are {0} and {1}'.format(sol1,sol2))

Hope This Helps!!!

3 0
3 years ago
Read 2 more answers
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