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ankoles [38]
3 years ago
15

Can someone please help me with these 2 questions *No links* Need help asap

Mathematics
1 answer:
poizon [28]3 years ago
5 0

Answer:

shown below

Step-by-step explanation:

GDO=21

x=3 and i cant figure out DOG or DGO

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3. Hardness

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Step-by-step explanation:

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3 years ago
Find x with the formulaaa<br><br>​
kotegsom [21]
10x+90=360
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Scoops ice cream shop serves 10 different flavors of ice cream three types of syrup and seven types of sprinkles if an ice cream
mariarad [96]
I think 50 but idk
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7 0
3 years ago
Help me with this question this was supposed to be due yesterday!
Inessa05 [86]

Answer: Both the mean and median decreased.

Step-by-step explanation:

The addition of the 500 lb baby elephant will have a huge impact on the mean, since you'll be finding the average (adding all numbers then dividing). So the only logical answer would be the chosen. The median will most likely either decrease or stay the same, but since staying the same isn't an option for the median, it's most likely going to be decrease.

[I do apologize in advance if it's wrong, and next time try submitting work on time :)) Hope I helped!]

8 0
4 years ago
2. The Welcher Adult Intelligence Test Scale is composed of a number of subtests. On one subtest, the raw scores have a mean of
IgorC [24]

Answer:

a) 37.31 b) 42.70 c) 0.57 d) 0.09

Step-by-step explaanation:

We are regarding a normal distribution with a mean of 35 and a standard deviation of 6, i.e., \mu = 35 and \sigma = 6. We know that the probability density function for a normal distribution with a mean of \mu and a standard deviation of \sigma is given by

f(x) = \frac{1}{\sqrt{2\pi}\sigma}\exp[-\frac{(x-\mu)^{2}}{2\sigma^{2}}]

in this case we have

f(x) = \frac{1}{\sqrt{2\pi}6}\exp[-\frac{(x-35)^{2}}{2(6^{2})}]

Let X be the random variable that represents a row score, we find the values we are seeking in the following way

a)  we are looking for a number x_{0} such that

P(X\leq x_{0}) = \int\limits^{x_{0}}_{-\infty} {f(x)} \, dx = 0.65, this number is x_{0}=37.31

you can find this answer using the R statistical programming languange and the instruction qnorm(0.65, mean = 35, sd = 6)

b) we are looking for a number  x_{1} such that

P(X\leq x_{1}) = \int\limits^{x_{1}}_{-\infty} {f(x)} \, dx = 0.9, this number is x_{1}=42.70

you can find this answer using the R statistical programming languange and the instruction qnorm(0.9, mean = 35, sd = 6)

c) we find this probability as

P(28\leq X\leq 38)=\int\limits^{38}_{28} {f(x)} \, dx = 0.57

you can find this answer using the R statistical programming languange and the instruction pnorm(38, mean = 35, sd = 6) -pnorm(28, mean = 35, sd = 6)

d) we find this probability as

P(41\leq X\leq 44)=\int\limits^{44}_{41} {f(x)} \, dx = 0.09

you can find this answer using the R statistical programming languange and the instruction pnorm(44, mean = 35, sd = 6) -pnorm(41, mean = 35, sd = 6)

6 0
4 years ago
Read 2 more answers
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