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ella [17]
3 years ago
10

Which statements are true about the ordered pair (−1, 5) and the system of equations?

Mathematics
2 answers:
Rudiy273 years ago
7 0
An ordered pair (x,y) is a solution to a system of equations if it makes all the equations true.
Let's check whether (–1, 5) makes the equations true.
Plugging –1 in the first equation for x and 5 in for y, we get
–1 + 5 = 4: TRUE
 Plugging –1 in the second equation for x and 5 in for y, we get
–1 – 5 = –6: TRUE

Since it makes both the equations true, it's a solution to the system of equations. So the answer choice is D, the 4th one. 
Elodia [21]3 years ago
6 0

Answer:

you answer would be A,B,D there all the answer u cant just have one also I

just took the test im from k12

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3 years ago
Andrea deposited 138 into her bank account. Write a integer to represent the deposit
Sonbull [250]
Hello!

Depositing just means adding, ao Andrea added 138 to her account.

The integer that would represent the doposite is: +138

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3 years ago
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Jlenok [28]

Answer:

x+2y=-7

Step-by-step explanation:

2y + x =-7

x+2y=-7

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Find three positive numbers whose sum is 140 and whose product is a maximum. (Enter your answers as a comma-separated list.)
Paladinen [302]

Answer:

\frac{140}{3}, \frac{140}{3}, \frac{140}{3}

Step-by-step explanation:

Let the numbers be x, y\ and\ z.

Such that:

x + y + z = 140

Make z the subject

z = 140 -x - y

For their product to be maximum, we have:

f(x,y,z) = xyz

Substitute z = 140 -x - y in f(x,y,z) = xyz

f(x,y) = xy(140 - x - y)

Open bracket

f(x,y) = 140xy - x^2y - xy^2

Differentiate w.r.t x and y

f_x=140y - 2xy - y^2

f_y=140x - x^2 - 2xy

Since the products are maximum, then f_x = f_y = 0

For f_x=140y - 2xy - y^2

140y - 2xy - y^2 = 0

Factorize:

y(140 - 2x - y) = 0

Split

y = 0\ or\ 140 - 2x - y = 0

Make y the subject

y = 0\ or\ y = 140 - 2x

For f_y=140x - x^2 - 2xy

140x - x^2 - 2xy = 0

---------------------------------------------------

Substitute y = 0

140x - x^2 -2x*0 = 0

140x - x^2 = 0

Factorize

x(140 - x)= 0

x = 0\ or\ 140-x = 0

x = 0\ or\ x = 140

---------------------------------------------------

Substitute y = 140 - 2x

140x - x^2 - 2xy = 0

140x - x^2 - 2x(140 - 2x) = 0

140x - x^2 - 280x + 4x^2 = 0

Re-arrange

4x^2 -x^2 +140x - 280x = 0

3x^2 -140x = 0

Factor x out

x(3x - 140) = 0

Divide through by x

3x - 140 = 0

3x = 140

x = \frac{140}{3}

Recall that: y = 140 - 2x

y = 140 - 2 * \frac{140}{3}

y = 140 - \frac{280}{3}

Take LCM

y = \frac{140*3-280}{3}

y = \frac{140}{3}

Recall that:

z = 140 -x - y

z = 140 - \frac{140}{3} - \frac{140}{3}

Take LCM

z =  \frac{3 * 140- 140 - 140}{3}

z =  \frac{140}{3}

Hence, the numbers are:

\frac{140}{3}, \frac{140}{3}, \frac{140}{3}

8 0
3 years ago
MATH!!! find the volume of the pyramid. pleaseee answer correctly and tell me how you got your answer.
bagirrra123 [75]

The area of polygons formulas to V=2.56m^2

We have to determine,

The volume of the pyramid.

<h3>What is the volume of the pyramid?</h3>

The volume of a pyramid is found using the formula,

V = (1/3) Bh

where 'B' is the base area and 'h' is the height of the pyramid.

hight =2.4m

base=1.4+1.8

base=3.2m

V = (1/3) (3.2)(2.4)

V=2.56m^2

As we know the base of a pyramid is any polygon,

we can apply the area of polygons formulas to find 'B.

V=2.56m^2.

To learn more about the volume visit:

brainly.com/question/1972490

#SPJ1

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2 years ago
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