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Gre4nikov [31]
3 years ago
11

What is the answer for 3/5 of 15

Mathematics
1 answer:
VARVARA [1.3K]3 years ago
6 0
3/5 of 15=n
n=9          
So, if you divide 3/5 of 15, you get 9 as your answer.                                     
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The variables x and y are inversely proportional, and y = 2 when x = 3. What is the value of y when x = 9?
givi [52]
If\ x\ and\ y\ are\ inversely\ proportional\ then\ xy\ is\ constans.\\\\9y=2\times 3\\\\9y=6\ \ \ \ \ \ /:9\\\\y=\frac{6}{9}\\\\y=\frac{2}{3}
7 0
4 years ago
Read 2 more answers
Ryan is X years old. Two times his age plus fifteen equals thirty-seven minus two. ( 2X + 15=37 - 2) Write an equation showing h
Misha Larkins [42]

Answer:

1) 10

2) 16

Step-by-step explanation:

1) 2x+15=37-2

2x+15=35

2x=35-15

2x=20

2 2

x=10

2)10x-8=9x+8

10x-9x=8+8

x=16

Hope this helps ❤

3 0
4 years ago
Guys I just went poop and there's no toilet paper please help what do I do oh my godddd​
iogann1982 [59]

Answer:

Use water to clean yourself and than just wash your hands afterward lol

Step-by-step explanation:

8 0
4 years ago
What number should be added to both sides of the equation to complete the square? x^2 – 6x = 5
NeTakaya
You will add ( \frac{-6}{2}  )^{2}
(-3)^{2}
9
5 0
3 years ago
6. Two observers, 7220 feet apart, observe a balloonist flying overhead between them. Their measures of the
MaRussiya [10]

Answer:

The ballonist is at a height of 3579.91 ft above the ground at 3:30pm.

Step-by-step explanation:

Let's call:

h the height of the ballonist above the ground,

a the distance between the two observers,

a_1 the horizontal distance between the first observer and the ballonist

a_2 the horizontal distance between the second observer and the ballonist

\alpha _1 and \alpha _2 the angles of elevation meassured by each observer

S the area of the triangle formed with the observers and the ballonist

So, the area of a triangle is the length of its base times its height.

S=a*h (equation 1)

but we can divide the triangle in two right triangles using the height line. So the total area will be equal to the addition of each individual area.

S=S_1+S_2 (equation 2)

S_1=a_1*h

But we can write S_1 in terms of \alpha _1, like this:

\tan(\alpha _1)=\frac{h}{a_1} \\a_1=\frac{h}{\tan(\alpha _1)} \\S_1=\frac{h^{2} }{\tan(\alpha _1)}

And for S_2 will be the same:

S_2=\frac{h^{2} }{\tan(\alpha _2)}

Replacing in the equation 2:

S=\frac{h^{2} }{\tan(\alpha _1)}+\frac{h^{2} }{\tan(\alpha _2)}\\S=h^{2}*(\frac{1 }{\tan(\alpha _1)}+\frac{1}{\tan(\alpha _2)})

And replacing in the equation 1:

h^{2}*(\frac{1 }{\tan(\alpha _1)}+\frac{1}{\tan(\alpha _2)})=a*h\\h=\frac{a}{(\frac{1 }{\tan(\alpha _1)}+\frac{1}{\tan(\alpha _2)})}

So, we can replace all the known data in the last equation:

h=\frac{a}{(\frac{1 }{\tan(\alpha _1)}+\frac{1}{\tan(\alpha _2)})}\\h=\frac{7220 ft}{(\frac{1 }{\tan(35.6)}+\frac{1}{\tan(58.2)})}\\h=3579,91 ft

Then, the ballonist is at a height of 3579.91 ft above the ground at 3:30pm.

6 0
3 years ago
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