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grin007 [14]
3 years ago
9

If 100C2 has a value of 4,950, what is the value of 100C98? A. 4,950 B. 99,000 C. 49,500 D. 9,900

Mathematics
2 answers:
diamong [38]3 years ago
4 0
<span>If 100C2 has a value of 4,950, what is the value of 100C98?
10C2 is the number of groups of 2 that can be formed from 100 objects.
Note: Each time a group of 2 is selected you automatically form
a second group of 98. Therefore: 10C2 = 10C98 = 4950 is your Answer</span>
Diano4ka-milaya [45]3 years ago
3 0
100C2 is a count of the number of sets of two you can drawfrom a set of 100 items. But every time you draw a set of 2 from 100 you haveautomatically determined a set of 98 that you did not select. so the answer is A. 4950
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Step-by-step explanation:

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2 years ago
When Mei does 17 push-ups and 6 sit-ups, it takes a total of 35 seconds. In comparison, she needs 41 seconds to do 20 push-ups a
Romashka [77]

Answer:

It takes 1 seconds for push-ups and 3 seconds for sit-ups for Mei to do exercise.

Step-by-step explanation:

Given:

Let the time taken for push-ups be 'x'.

Let the time taken for sit-ups be 'y'.

Now Given:

17 push-ups and 6 sit-ups, it takes a total of 35 seconds.

So we can say that;

17x+6y=35 \ \ \ \ equation \ 1

Also Given:

41 seconds to do 20 push-ups and 7 sit-ups.

so we can say that;

20x+7y=41 \ \ \ \ equation \ 2

Now Multiplying equation 1 by 7 we get;

7(17x+6y)=35\times7\\\\119x+42y= 245 \ \ \ \ equation \ 3

Now Multiplying equation 2 by 6 we get;

6(20x+7y)=41\times6\\\\120x+42y = 246 \ \ \ \ equation\ 4

Now Subtracting equation 3 from equation 4 we get;

120x+42y-(119x+42y)=246-245\\\\120x+42y-119x-42y=1\\\\x=1\ sec

Now substituting the value of x in equation 1 we get;

17x+6y=35\\\\17\times1+6y=35\\\\17+6y=35\\\\6y=35-17\\\\6y= 18\\\\y=\frac{18}6 = 3\ seconds

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