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tino4ka555 [31]
3 years ago
5

How do you solve linear equations in three variables?

Mathematics
2 answers:
barxatty [35]3 years ago
8 0
''Pick any two pairs of equations<span> from the system. Eliminate the same </span>variable<span> from each pair using the Addition/Subtraction method. Solve the system of the two new </span>equations<span> using the Addition/Subtraction method.''</span>
sleet_krkn [62]3 years ago
5 0
Really depends upon the 3 equations.
If you can find x in terms of y and z in one of the problems,
then substitute this back into the other two equations, then solve the 2 equations and two unknowns.
There are other elimination techniques but difficult to explain.
Or use the matrix solution technique in the TI calculator and use "rrde" to solve.
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Given that f(x)=x^2-4x -3 and g(x)=x+3/4 solve for f(g(x)) when x=9
SSSSS [86.1K]

Answer:

f(g(9)) = 945/16

Step-by-step explanation:

To find f(g(x)), you have to substitute g(x) wherever there is an x in f(x).

g(x) = x + 3/4

f(x) = x² - 4x - 3

f(g(x)) = (x + 3/4)² - 4(x + 3/4) - 3

f(g(x)) = x² + 3/2x + 9/16 - 4x + 3 - 3

f(g(x)) = x² - 5/2x + 9/16 + 3 - 3

f(g(x)) = x² - 5/2x + 9/16

Now, put a 9 wherever there is an x in f(g(x)).

f(g(9)) = (9)² - 5/2(9) + 9/16

f(g(9)) = 81 - 5/2(9) + 9/16

f(g(9)) = 81 - 45/2 + 9/16

f(g(9)) = 117/2 + 9/16

f(g(9)) = 945/16

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