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BaLLatris [955]
3 years ago
7

Solve for Y py+qy= -4y+8

Mathematics
1 answer:
BlackZzzverrR [31]3 years ago
4 0

Answer:

This is a step by step procedure to get the value of y.

First: Move all terms to the left side and set equal to zero.

Second: Then set each factor equal to zero.

The application is:

Given: py+7=6y+q

-6y -7 -6y -7 = 0

(p-6)y = q-7

divide both sides by p-6

y=(q-7)/(p-6)

Answer is y = (q – 7) / (p – 6)

Step-by-step explanation:

i hope i helped : )

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a_sh-v [17]

Answer: 40

Step-by-step explanation:

Given

Jar contains 200 old dimes

Chances to pick the 1960s is 20% i.e. 1960s is 20% of 200 old dimes

So, we can write

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8 0
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8x10to the 3rd power
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Answer:

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Step-by-step explanation:

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Read 2 more answers
Simplify. -10m+2m^4-13m-20m^4
Ulleksa [173]
First one:

you can add -10m and -13m but you can't add -10m and 2m^4 becuase the powers aren't the same so

when adding the like terms
look at the:
powers, (x^3 adds with x^3)
placehloder letter (x adds with x and y adds with y and so on)

-10m+2m^4-13m-20m^4
powers: m^1 and M^4
placeholders: all m


add
-10m-13m+2m^4-20m^4
-23m-18m^4




second one:
when multiplying exponents, you add with like
so if you multipliy
x^2yz^3 times x^4y^2z^2 thne you would get x^6y^3z^5
when multiply with coeficients
2x^2yz^3 times 4x^4y^2z^2=8x^6y^3z^5
so using associative property a(bc)=(ab)c
2/3 times p^4 times y^3 times y^4 times s^5 times 6 times p^2 times s^3
group like terms

(2/3 times 6) times (p^4 times p^2) times (y^3 times y^4) times (s^5 times s^3)
(4) times (p^6) times (y^7) times (s^8)
4p^6y^7s^8

8 0
3 years ago
What is the answer to this? Plz answer! It's due tomorrow!!!!!​
Leya [2.2K]

Answer: the third answer (C)

Step-by-step explanation:

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PLLZZZZZZZ PLZZZZ PLZZZZ HELP ME OUT BRAINLIREST PLUS POINTS PLZ ALL I NEED IS ANSWER NO WORK
Nastasia [14]

Answer:

(3/2x)+14

Step-by-step explanation:


3 0
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