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3 years ago

Solve for Y py+qy= -4y+8

Mathematics

1 answer:

BlackZzzverrR [31]3 years ago

4 0

Answer:

This is a step by step procedure to get the value of y.

First: Move all terms to the left side and set equal to zero.

Second: Then set each factor equal to zero.

The application is:

Given: py+7=6y+q

-6y -7 -6y -7 = 0

(p-6)y = q-7

divide both sides by p-6

y=(q-7)/(p-6)

Answer is y = (q – 7) / (p – 6)

Step-by-step explanation:

i hope i helped : )

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Help, please iiiiiiiiiiiiiii nnnnnnnnnneeeeeeedddddd iiiiiiiiitttttt

trasher [3.6K]

Answer:it’s a

Step-by-step explanation:

7 0

2 years ago

In order to solve the system of linear equations, the coefficients of one of the variables must be the same number but opposite

Mashutka [201]

Answer:

Step-by-step explanation:

because both equations do not have matching numbers for the x or y variable, and both equations are positive you are going to have to multiply each equation by a number so that there will be at least one variable with the same number but with opposite signs.

it does not matter which variable you choose.

lets use y because 2 and 3 are smaller then 2 and 5.

so lets multiply the first equation by 2 in order to get y equal to 6.

2(2x)+2(3y)=(2)6

(do not forget to multiply what the equation is equal to also)

4x+6y=12

now for the second equation we need y to equal negative 6

-3(5x)+-3(2y)=-3(4)

-15x-6y=-12

now lets put the 2 new equations next to each other and see what we can cancel out

4x+6y=12

-15x-6y=-12

-11x=0

x=0

now plug 0 in for x and solve for y (it does not matter which of the 4 equations you choose to solve.

2(0)+3y=6

3y=6

y=2

so your answer is x=0, y=2

8 0

2 years ago

The sum of two terms of gp is 6 and that of first four terms is 15/2.Find the sum of first six terms.

Gnoma [55]

Given:

The sum of two terms of GP is 6 and that of first four terms is $\dfrac{15}{2}.$

To find:

The sum of first six terms.

Solution:

We have,

$S_2=6$

$S_4=\dfrac{15}{2}$

Sum of first n terms of a GP is

$S_n=\dfrac{a(1-r^n)}{1-r}$ ...(i)

Putting n=2, we get

$S_2=\dfrac{a(1-r^2)}{1-r}$

$6=\dfrac{a(1-r)(1+r)}{1-r}$

$6=a(1+r)$ ...(ii)

Putting n=4, we get

$S_4=\dfrac{a(1-r^4)}{1-r}$

$\dfrac{15}{2}=\dfrac{a(1-r^2)(1+r^2)}{1-r}$

$\dfrac{15}{2}=\dfrac{a(1+r)(1-r)(1+r^2)}{1-r}$

$\dfrac{15}{2}=6(1+r^2)$ (Using (ii))

Divide both sides by 6.

$\dfrac{15}{12}=(1+r^2)$

$\dfrac{5}{4}-1=r^2$

$\dfrac{5-4}{4}=r^2$

$\dfrac{1}{4}=r^2$

Taking square root on both sides, we get

$\pm \sqrt{\dfrac{1}{4}}=r$

$\pm \dfrac{1}{2}=r$

$\pm 0.5=r$

Case 1: If r is positive, then using (ii) we get

$6=a(1+0.5)$

$6=a(1.5)$

$\dfrac{6}{1.5}=a$

$4=a$

The sum of first 6 terms is

$S_6=\dfrac{4(1-(0.5)^6)}{(1-0.5)}$

$S_6=\dfrac{4(1-0.015625)}{0.5}$

$S_6=8(0.984375)$

$S_6=7.875$

Case 2: If r is negative, then using (ii) we get

$6=a(1-0.5)$

$6=a(0.5)$

$\dfrac{6}{0.5}=a$

$12=a$

The sum of first 6 terms is

$S_6=\dfrac{12(1-(-0.5)^6)}{(1+0.5)}$

$S_6=\dfrac{12(1-0.015625)}{1.5}$

$S_6=8(0.984375)$

$S_6=7.875$

Therefore, the sum of the first six terms is 7.875.

5 0

2 years ago

Y=2x-pq rearrange the formula to make x the subject

professor190 [17]

Y=2x-pq
2x=y+pq
x=(y+pq) / 2

7 0

3 years ago

The blue string is 0.98 meters long. The

Yuliya22 [10]

Answer:

22 centimeters

Step-by-step explanation:

1. See how many centimeters are in a meter:

There is 100 centimeters in one meter

2. Multiply each number by 100 to convert the meters to centimeters 

0.98 x 100= 98

0.76 x 100 = 76

3. Subtract to find the difference

98 - 76 = 22

Hence, the blue string is 22 centimeters longer than the yellow string.

have great night! :D

4 0

2 years ago