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BaLLatris [955]
3 years ago
7

Solve for Y py+qy= -4y+8

Mathematics
1 answer:
BlackZzzverrR [31]3 years ago
4 0

Answer:

This is a step by step procedure to get the value of y.

First: Move all terms to the left side and set equal to zero.

Second: Then set each factor equal to zero.

The application is:

Given: py+7=6y+q

-6y -7 -6y -7 = 0

(p-6)y = q-7

divide both sides by p-6

y=(q-7)/(p-6)

Answer is y = (q – 7) / (p – 6)

Step-by-step explanation:

i hope i helped : )

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Melissa Silva borrowed $6,300 from the bank. If she has already repaid
melamori03 [73]
The remaining balance would be $3,600.

$6,300/7 = 900 x 3 = $2,700
$6,300 - $2,700 = $3,600
8 0
3 years ago
What is the absolute value of the complex number -4-√2
Zepler [3.9K]
|a+bi| = √(a² + b²)

-4-√2 i -> take a = -4 and b = -√2

|-4-√2 i| = √[ (-4)² + (<span>-√2)² ]
               = </span><span>√[ 16 + 2<span> ]
               </span></span><span>= √[ 18 ]</span> = <span>√[ 9 * 2 ]
               = 3√2
the absolute value is 3√2</span>

6 0
3 years ago
A cylindrical tank with radius 3 m is being filled with water at a rate of 4 m3/min. How fast is the height of the water increas
Fittoniya [83]

Height of the water increasing is at rate of  #(dh)/(dt)=3/(25 pi)m/(min)#

<h3>How to solve?</h3>

With related rates, we need a function to relate the 2 variables, in this case it is clearly volume and height. The formula is:

#V=pi r^2 h#

There is radius in the formula, but in this problem, radius is constant so it is not a variable. We can substitute the value in:

#V=pi (5m)^2 h#

Since the rate in this problem is time related, we need to implicitly differentiate wrt (with respect to) time:

#(dV)/(dt)=(25 m^2) pi (dh)/(dt)#

In the problem, we are given #3(m^3)/min# which is #(dV)/(dt)#.

So we need to substitute this in:

#(dh)/(dt)=(3m^3)/(min (25m^2) pi)=3/(25 pi)m/(min)#

Hence,  Height of the water increasing is at rate of  #(dh)/(dt)=3/(25 pi)m/(min)#

<h3>Formula used: </h3>

#V=pi r^2 h#

To Learn more visit:

brainly.com/question/4313883

#SPJ4

4 0
2 years ago
Read 2 more answers
There are 65 children in the sixth grade. The ratio of boys to girls 3 to 2. A) how many girls are in the grade?
Akimi4 [234]

Given that,

Total number of children = 65

The ratio of boys to girls is 3 :2.

To find,

The number of girls in the grade.

Solution,

Let there are 3x girls and 2x boys.

ATQ,

3x + 2x = 65

5x = 65

x = 13

So, no of girls = 3x

= 3(13)

= 39

Hence, there are 39 girls in the grade.

5 0
3 years ago
BD is the angle bisector of
AlexFokin [52]

Note: Let us consider, we need to find the m\angle ABC and m\angle DBC.

Given:

In the given figure, BD is the angle bisector of ABC.

To find:

The m\angle ABC and m\angle DBC.

Solution:

BD is the angle bisector of ABC. So,

m\angle ABD=m\angle DBC

3x=x+20

3x-x=20

2x=20

Divide both sides by 2.

x=\dfrac{20}{2}

x=10

Now,

m\angle DBC=(x+20)^\circ

m\angle DBC=(10+20)^\circ

m\angle DBC=30^\circ

And,

m\angle ABC=(3x)^\circ+(x+20)^\circ

m\angle ABC=(4x+20)^\circ

m\angle ABC=(4(10)+20)^\circ

m\angle ABC=(40+20)^\circ

m\angle ABC=60^\circ

Therefore, m\angle DBC=30^\circ,m\angle ABD=30^\circ and m\angle ABC=60^\circ.

8 0
2 years ago
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