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Mathematics

1 answer:

Vitek1552 [10]2 years ago

5 0

You multiply the binomial by the whole trinomial.

So 5x^2 (5x^3 - 6x^2 - 5) and then -2x (5x^3 - 6x^2 - 5)

then solve so it is:
25x^5 - 30x^4 - 25x^2 - 10x^4 + 12x^3 + 10x.

Then you simplify to:
25x^5 - 40x^4 + 12x^3 - 25x^2 + 10x

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I need some help with this

Korvikt [17]

The following can be deduced from the expressions

m ∠ D = 4 × m ∠ A
m ∠ B = 3 × m ∠ A-12

Please note that the sum of angles in a triangle is 180 degress. Therefore,

M∠ A + m ∠ B + m ∠ D = 180equation(3)

Substitute for equation 1 and 2 in equation 3 as shown below

m ∠ A + 3 × m ∠ A - 12^0 + 4 x m ∠ A =180^0
m ∠ A + 3 × m ∠ A + 4 x m ∠ A = 180^0+12^0
8m ∠ A = 192^0
m ∠ A= 192^0/8
m ∠ A=24^0

Substitute for m∠A= 24 in equation 1 and 2 as shown below

m ∠ D = 4 × m ∠ A
m ∠ D = 4 × 24^0
m ∠ D = 96^0
m ∠ B = 3 × mA - 12^0
m ∠ B = 3 × 24^0 - 12
m ∠ B = 72^0 - 12^0

,

∠= °

∠= °

∠= °

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Rom4ik [11]

Using tally marks make a table of the given subjects English (4), Urdu (3), Maths (4), Science (3) and Computer (2).

The given data are English, Maths, Urdu, Science, English, Urdu, Science, Maths, English, Computer, Maths, Urdu, Science, Maths, Computer, and English.

<h3>What is a data table?</h3>

A table is an arrangement of information or data, typically in rows and columns, or possibly in a more complex structure. Tables are widely used in communication, research, and data analysis.

The data table for the given data is given below:

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MakcuM [25]

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Step-by-step explanation:

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2 years ago

Could someone help me rnnn?

GuDViN [60]

Answer:

vertex = (0, -4)

equation of the parabola: $y=3x^2-4$

Step-by-step explanation:

Given:

y-intercept of parabola: -4
parabola passes through points: (-2, 8) and (1, -1)

Vertex form of a parabola: $y=a(x-h)^2+k$

(where (h, k) is the vertex and $a$ is some constant)

Substitute point (0, -4) into the equation:

$\begin{aligned}\textsf{At}\:(0,-4) \implies a(0-h)^2+k &=-4\\ah^2+k &=-4\end{aligned}$

Substitute point (-2, 8) and $ah^2+k=-4$ into the equation:

$\begin{aligned}\textsf{At}\:(-2,8) \implies a(-2-h)^2+k &=8\\a(4+4h+h^2)+k &=8\\4a+4ah+ah^2+k &=8\\\implies 4a+4ah-4&=8\\4a(1+h)&=12\\a(1+h)&=3\end{aligned}$