What is 12.8 rounded to the nearest hundred

From her eye, which stands 1,61 meters above the ground, Savannah measures the

Cloud [144]

Answer:

152.99 m

Step-by-step explanation:

Using the solution diagram attached below :

We can obtain the height, h of skyscraper to the position of her eye level using trigonometry ;

Tan θ = opposite / Adjacent

Tan 24 = h / 340

h = tan 24 * 340

h = 151.37775

Hence, the height will be (h + distance from eyelevel to ground)

151.37775 + 1.61

= 152.98775

= 152.99 m

4 0

2 years ago

CAN SOMEONE PLEASE HELP WITH QUESTIONS 3 THROUGH 11?? YOU DON’T EVEN HAVE TO DO ALL OF THEM JUST THE ONES U FEEL LIKE DOING (ILL

adell [148]

Answer:

3. 3/2

4. -1/3

5. -3.5

6. -6and 2/3

7. -18and 13/24

8. 1/18

9.-2.6

10.-1.83

11. 14.963

Step-by-step explanation:

HOPE THIS HELPS, if not see me in the comments

BRANILIEST PLZZZ

6 0

2 years ago

Manuel wants to build a model of Captain America's famous shield out of cardboard. The outer ring of the shield is colored red.

zmey [24]

Answer:

615.44 in²

Step-by-step explanation:

The shape of Captain America's shield = Circular

The area of a circle = πr²

The radius of the whole shield = 14 inches.

The first ring = Red ring

Hence, the area of the red ring =

π = 3.14

3.14 × 14²

= 615.44 in²

The area of the space he needs to paint red is 615.44 in²

7 0

2 years ago

*HELP PLEASE* Will get BRAINLIEST answer!!!!

photoshop1234 [79]

When solving these proportions we just remember when moving a number from one side to the other if it started in the numerator it ends up in the denominator and vice versa.

I'll do it in two steps here for teaching purposes; it's not too hard to go directly to the answer.

$\dfrac{13}{7} = \dfrac{10}{v}$

$13 v = 7(10)$

$v= \dfrac{7 \cdot 10 }{13} = \dfrac{70}{13} \approx 5.4$

5 0

3 years ago

Read 2 more answers

A certain geneticist is interested in the proportion of males and females in the population who have a minor blood disorder. In

lord [1]

Answer:

95% confidence interval for the difference between the proportions of males and females who have the blood disorder is [-0.064 , 0.014].

Step-by-step explanation:

We are given that a certain geneticist is interested in the proportion of males and females in the population who have a minor blood disorder.

A random sample of 1000 males, 250 are found to be afflicted, whereas 275 of 1000 females tested appear to have the disorder.

Firstly, the pivotal quantity for 95% confidence interval for the difference between population proportion is given by;

P.Q. = $\frac{(\hat p_1-\hat p_2)-(p_1-p_2)}{\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+ \frac{\hat p_2(1-\hat p_2)}{n_2}} }$ ~ N(0,1)

where, $\hat p_1$ = sample proportion of males having blood disorder= $\frac{250}{1000}$ = 0.25

$\hat p_2$ = sample proportion of females having blood disorder = $\frac{275}{1000}$ = 0.275

$n_1$ = sample of males = 1000

$n_2$ = sample of females = 1000

$p_1$ = population proportion of males having blood disorder

$p_2$ = population proportion of females having blood disorder

Here for constructing 95% confidence interval we have used Two-sample z proportion statistics.

So, 95% confidence interval for the difference between the population proportions, ( $p_1-p_2$ ) is ;

P(-1.96 < N(0,1) < 1.96) = 0.95 {As the critical value of z at 2.5% level

of significance are -1.96 & 1.96}

P(-1.96 < $\frac{(\hat p_1-\hat p_2)-(p_1-p_2)}{\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+ \frac{\hat p_2(1-\hat p_2)}{n_2}} }$ < 1.96) = 0.95

P( $-1.96 \times {\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+ \frac{\hat p_2(1-\hat p_2)}{n_2}} }$ < ${(\hat p_1-\hat p_2)-(p_1-p_2)}$ < $1.96 \times {\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+ \frac{\hat p_2(1-\hat p_2)}{n_2}} }$ ) = 0.95

P( $(\hat p_1-\hat p_2)-1.96 \times {\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+ \frac{\hat p_2(1-\hat p_2)}{n_2}} }$ < ( $p_1-p_2$ ) < $(\hat p_1-\hat p_2)+1.96 \times {\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+ \frac{\hat p_2(1-\hat p_2)}{n_2}} }$ ) = 0.95

95% confidence interval for ( $p_1-p_2$ ) =

[ $(\hat p_1-\hat p_2)-1.96 \times {\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+ \frac{\hat p_2(1-\hat p_2)}{n_2}} }$ , $(\hat p_1-\hat p_2)+1.96 \times {\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+ \frac{\hat p_2(1-\hat p_2)}{n_2}} }$ ]

= [ $(0.25-0.275)-1.96 \times {\sqrt{\frac{0.25(1-0.25)}{1000}+ \frac{0.275(1-0.275)}{1000}} }$ , $(0.25-0.275)+1.96 \times {\sqrt{\frac{0.25(1-0.25)}{1000}+ \frac{0.275(1-0.275)}{1000}} }$ ]

= [-0.064 , 0.014]

Therefore, 95% confidence interval for the difference between the proportions of males and females who have the blood disorder is [-0.064 , 0.014].

8 0

3 years ago