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3 years ago

Find the magnitude and direction of r+u please help !!

Mathematics

1 answer:

solniwko [45]3 years ago

3 0

Answer:

5.4 cm; 133 degrees

Step-by-step explanation:

hope this helps

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What is 10 3/4-3 1/2

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The answer is 7 1/4
Or 29/4 as an improper fraction

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A line graph, or line chart, shows info as a series of data points that are connected by line segments.

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carson walks his dog 6 blocks south to the park. Next they jog 5 blocks east to go swimming at the pond. How many blocks did car

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3 years ago

Two cargo ships spot a signal fire on a small island. The captains know they are 140 feet

Irina18 [472]

The distance from Ship B to the signal fire at point C is $405.4 \mathrm{ft}$

Explanation:

It is given that two ships A and B are at a distance 140 ft from each other.

The angle formed by ship A is 82º and the angle formed by ship B is 78º.

To determine the distance from ship B to the signal fire at point C, we need to know the another angle.

Hence, we have,

$\begin{aligned}\angle A+\angle B+\angle C &=180^{\circ} \\82^{\circ}+78^{\circ}+\angle C &=180^{\circ} \\160^{\circ}+\angle C &=180^{\circ} \\\angle C &=20^{\circ}\end{aligned}$

Now, we shall solve the problem using the law of sines,

$\frac{\sin A}{a}=\frac{\sin C}{c}$

Substituting the values, we have,

$\frac{\sin 82^{\circ}}{a}=\frac{\sin 20^{\circ}}{140}$

$\frac{0.9903}{a}=\frac{0.3420}{140}$

Simplifying, we get,

$a=\frac{0.9903 \times 140}{0.3420}$

$a=405.4$

Thus, the distance from Ship B to the signal fire at point C is $405.4 \mathrm{ft}$

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3 years ago

Alexis wanted to understand whether grade level had any relationship to their opinion on extending the school day. She surveyed

MakcuM [25]

Actually there is enough information to solve this problem. First, let us find the total per row and per column.

(see attached pic)

P(Grade 10 | opposed) with P(opposed | Grade 10)

P(Grade 10 | opposed) = Number in Grade 10 who are opposed / Total number of Opposed (column)

P(Grade 10 | opposed) = 13 / 41 = 0.3171

P(opposed | Grade 10) = Number in Grade 10 who are opposed / Total number in Grade 10 (row)

P(opposed | Grade 10) = 13 / 32 = 0.4063

Therefore:

P(Grade 10 | opposed) IS NOT EQUAL P(opposed | Grade 10), hence they are dependent events.

Answer:

P(Grade 10 | opposed) < P(opposed | Grade 10)

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