Assuming 100 kw bulb
<span>We'll start by figuring out how much energy in
kilowatt-hours the light bulb uses per year. We multiply how much power it uses
in kilowatts, by the number of hours in a year. That gives 0.1 kW x 8,760 hours
or </span>876 kWh x 9 bulbs = 7884 kWh
The electricity produced by 4 tons x 2460
kWh/ton = 9840 kwh
<span>Since the produced electricity is bigger so it
is enough</span>
Answer:
BEN
Step-by-step explanation:
Answer:
<h3>#1</h3>
<u>The system of equations:</u>
- 2x + 7y = -11
- 3x + 5y = -22
Solve by elimination.
<u>Triple the first equation, double the second one, subtract the second from the first and solve for y:</u>
- 3(2x + 7y) - 2(3x + 5y) = 3(-11) - 2(-22)
- 6x + 21y - 6x - 10y = -33 + 44
- 11y = 11
- y = 1
<u>Find x:</u>
- 2x + 7*1 = -11
- 2x = -11 - 7
- 2x = -18
- x = -9
<u>The solution is:</u>
<h3>#2</h3>
<u>Simplifying in steps:</u>
- 8u - 29 > -3(3 - 4u)
- 8u - 29 > - 9 + 12u
- 12u - 8u < -29 + 9
- 4u < -20
- u < -5
C C C C C C C C is the answer
I think this question is technically asking
196.20 is what percent of 180, if so it would be 109%
https://www.percentagecal.com/answer/180-is-what-percent-of-196