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VashaNatasha [74]
3 years ago
10

Uppose you have a bag of marbles and of the marbles are . If you choose one without​ looking, the probability you choose marble

is
. How can you write this probability as a​ decimal? Write this probability as a decimal. Use a word or phrase to describe this probability.

How do you change the fraction to a​ decimal?
A. Multiply the numerator and denominator by .
B. Divide the denominator by the numerator.
C Divide the numerator by the denominator..
D. Multiply the numerator by the denominator.
Mathematics
1 answer:
ddd [48]3 years ago
5 0
C. Divide the numerator by the denominator.
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describe the steps you would take to determine the distance in miles between two towns that are 200 kilometers apart
MaRussiya [10]
It will be -200 kilometers because you gotta get a ruler
6 0
4 years ago
A sled is being pulled across a floor by two ropes such that the angle between them is 40°. If the forces on the ropes are 100 p
Dafna1 [17]

Answer:

option 4 ⇒ 236 lb.

Step-by-step explanation:

Best explanation of the question is as shown in the attached figure.

we will use the parallelogram method to calculate resultant force.

to get the length of the resultant force ⇒ use the cosines law

The cosine law is a² = b² + c² - 2 * b * c * cos (∠A)

Applying at the question where b = F₁  , c = F₂  and  ∠A = ∠x

Given that F₁ = 100 pounds  , F₂ = 150 pounds  and  ∠x = 180° - 40° = 140°

∴ (Resultant force)² = 100² + 150² - 2 * 100 * 150 * cos (∠140) = 55481

∴ Resultant force = √55481 = 235.54 ≅ 236 pounds

The answer is option 4 ⇒ 236 lb.

8 0
3 years ago
A=2 b=3 c=4<br><br> 1) ab - c =<br> 2) 6c - 2b=<br> 3) a + b - c + 5 =<br> 4) 7c - 2a =
bekas [8.4K]

Step-by-step explanation:

1)ab-c

=2(3)-4

=6-4

=2

2)6c-2b

=6(4)-2(3)

=24-6

=18

3)a+b-c+5

=2+3-4+5

=10-4

=6

5)7c-2a

=7(4)-2(2)

=28-4

=24

7 0
4 years ago
Read 2 more answers
Does there exist a di↵erentiable function g : [0, 1] R such that g'(x) = f(x) for all x 2 [0, 1]? Justify your answer
agasfer [191]

Answer:

No; Because g'(0) ≠ g'(1), i.e. 0≠2, then this function is not differentiable for g:[0,1]→R

Step-by-step explanation:

Assuming:  the function is f(x)=x^{2} in [0,1]

And rewriting it for the sake of clarity:

Does there exist a differentiable function g : [0, 1] →R such that g'(x) = f(x) for all g(x)=x² ∈ [0, 1]? Justify your answer

1) A function is considered to be differentiable if, and only if  both derivatives (right and left ones) do exist and have the same value. In this case, for the Domain [0,1]:

g'(0)=g'(1)

2) Examining it, the Domain for this set is smaller than the Real Set, since it is [0,1]

The limit to the left

g(x)=x^{2}\\g'(x)=2x\\ g'(0)=2(0) \Rightarrow g'(0)=0

g(x)=x^{2}\\g'(x)=2x\\ g'(1)=2(1) \Rightarrow g'(1)=2

g'(x)=f(x) then g'(0)=f(0) and g'(1)=f(1)

3) Since g'(0) ≠ g'(1), i.e. 0≠2, then this function is not differentiable for g:[0,1]→R

Because this is the same as to calculate the limit from the left and right side, of g(x).

f'(c)=\lim_{x\rightarrow c}\left [\frac{f(b)-f(a)}{b-a} \right ]\\\\g'(0)=\lim_{x\rightarrow 0}\left [\frac{g(b)-g(a)}{b-a} \right ]\\\\g'(1)=\lim_{x\rightarrow 1}\left [\frac{g(b)-g(a)}{b-a} \right ]

This is what the Bilateral Theorem says:

\lim_{x\rightarrow c^{-}}f(x)=L\Leftrightarrow \lim_{x\rightarrow c^{+}}f(x)=L\:and\:\lim_{x\rightarrow c^{-}}f(x)=L

4 0
4 years ago
Solve using Substitution<br> y = -1x - 5<br> 4x - 8y = 4
Liula [17]

Answers:

Step-by-step explanations:

4 0
3 years ago
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