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VashaNatasha [74]
2 years ago
10

Uppose you have a bag of marbles and of the marbles are . If you choose one without​ looking, the probability you choose marble

is
. How can you write this probability as a​ decimal? Write this probability as a decimal. Use a word or phrase to describe this probability.

How do you change the fraction to a​ decimal?
A. Multiply the numerator and denominator by .
B. Divide the denominator by the numerator.
C Divide the numerator by the denominator..
D. Multiply the numerator by the denominator.
Mathematics
1 answer:
ddd [48]2 years ago
5 0
C. Divide the numerator by the denominator.
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A triangle has a base of 7 1/8 feet and height 7 1/5 ft. what is the area as a mixed number
sleet_krkn [62]

The answer is 25 13/20 square feet.

In order to complete this operation, it is first best to change your mixed numbers into improper fractions.

7 1/8 = 57/8

7 1/5 = 36/5

Now that we have these, we can put them into the triangle formula.

A = 1/2bh

A = (1/2)(57/8)(36/5)

A = 1026/40

You can then simplify this fraction by dividing the top and bottom by a factor of 2.

A = 513/20

Then, because we know 20 goes into 500, 25 times, we can pull that out and be left with a remainder of 13/20.

A = 25 13/20

8 0
3 years ago
Which system is the solution of the graph?
antoniya [11.8K]
Let me know what grade is learning this
3 0
3 years ago
How to solve foil methods give me a example please
BARSIC [14]
FOIL: First, Inner, Outer, Last.
(2x+3)(3x+2)
First: 2x•3x=6x^2 Inner: 3x•3=9x
Outer: 2x•2=4x Last:3•2=6
6x^2+9x+4x+6= 6x^2+13x+6
8 0
3 years ago
Chang is estimating the volume of his bathtub the actual volume of his bathtub is 37 gal chang’s estimate is 31 gal find the abs
stepladder [879]
<h3>The absolute error is 6</h3><h3>The percent error is 16.22 %</h3>

<em><u>Solution:</u></em>

Given that,

Actual volume of his bathtub is 37 gal

Estimate is 31 gal

<em><u>Find the absolute error</u></em>

Absolute Error = | Measured Value - Actual Value |

Absolute Error = | 31 - 37 |

Absolute Error = 6

<em><u>Find the percent error</u></em>

Percent\ error = \frac{\text{estimate - actual}}{actual} \times 100

Substituting we get,

percent\ error = \frac{31-37}{37} \times 100\\\\percent\ error = \frac{-6}{37} \times 100\\\\percent\ error = -16.22

Negative sign means percent decrease

Thus percent error is 16.22 %

5 0
2 years ago
Suppose a random variable x is best described by a uniform probability distribution with range 22 to 55. Find the value of a tha
const2013 [10]

Answer:

(a) The value of <em>a</em> is 53.35.

(b) The value of <em>a</em> is 38.17.

(c) The value of <em>a</em> is 26.95.

(d) The value of <em>a</em> is 25.63.

(e) The value of <em>a</em> is 12.06.

Step-by-step explanation:

The probability density function of <em>X</em> is:

f_{X}(x)=\frac{1}{55-22}=\frac{1}{33}

Here, 22 < X < 55.

(a)

Compute the value of <em>a</em> as follows:

P(X\leq a)=\int\limits^{a}_{22} {\frac{1}{33}} \, dx \\\\0.95=\frac{1}{33}\cdot \int\limits^{a}_{22} {1} \, dx \\\\0.95\times 33=[x]^{a}_{22}\\\\31.35=a-22\\\\a=31.35+22\\\\a=53.35

Thus, the value of <em>a</em> is 53.35.

(b)

Compute the value of <em>a</em> as follows:

P(X< a)=\int\limits^{a}_{22} {\frac{1}{33}} \, dx \\\\0.95=\frac{1}{33}\cdot \int\limits^{a}_{22} {1} \, dx \\\\0.49\times 33=[x]^{a}_{22}\\\\16.17=a-22\\\\a=16.17+22\\\\a=38.17

Thus, the value of <em>a</em> is 38.17.

(c)

Compute the value of <em>a</em> as follows:

P(X\geq  a)=\int\limits^{55}_{a} {\frac{1}{33}} \, dx \\\\0.85=\frac{1}{33}\cdot \int\limits^{55}_{a} {1} \, dx \\\\0.85\times 33=[x]^{55}_{a}\\\\28.05=55-a\\\\a=55-28.05\\\\a=26.95

Thus, the value of <em>a</em> is 26.95.

(d)

Compute the value of <em>a</em> as follows:

P(X\geq  a)=\int\limits^{55}_{a} {\frac{1}{33}} \, dx \\\\0.89=\frac{1}{33}\cdot \int\limits^{55}_{a} {1} \, dx \\\\0.89\times 33=[x]^{55}_{a}\\\\29.37=55-a\\\\a=55-29.37\\\\a=25.63

Thus, the value of <em>a</em> is 25.63.

(e)

Compute the value of <em>a</em> as follows:

P(1.83\leq X\leq  a)=\int\limits^{a}_{1.83} {\frac{1}{33}} \, dx \\\\0.31=\frac{1}{33}\cdot \int\limits^{a}_{1.83} {1} \, dx \\\\0.31\times 33=[x]^{a}_{1.83}\\\\10.23=a-1.83\\\\a=10.23+1.83\\\\a=12.06

Thus, the value of <em>a</em> is 12.06.

7 0
3 years ago
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