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3 years ago

Find the following percents. Round to the nearest thousandth when necessary. 6% of 300.

Mathematics

1 answer:

finlep [7]3 years ago

3 0

300/x=100/6

(300/x)*x=(100/6)*x

300=16.6666666667*x

300/16.6666666667=x

x=18

Therefore the answer is "18."

Hope this helps!

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12 7/12 subtracted by 5 14/5

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4 0

3 years ago

Let f(x) =x+5 and g(x)=x^2-3 then f(g(x)) =?

guajiro [1.7K]

Answer:

Option (a) is true.

Step-by-step explanation:

Given the function

$f(x)=x+5$

$g\left(x\right)=x^2-3$

(f∘g)(x) = f(g(x)) = f(x²-3) = (x²-3)+5

= x² + 2

Thus,

f(g(x)) = x² + 2

Therefore, option (a) is true.

6 0

2 years ago

Tiffany took her friends out to dinner. If the dinner was $29.53 and she gave a 20% tip, how much money did she spend on dinner?

gladu [14]

Answer: The answer is 35.43 because 29.53 times 20% is 5.90, so you add 5.90 to 29.53 to get 35.43.

7 0

2 years ago

On a coordinate plane, the x-axis is labeled Pepperoni Pizzas and the y-axis is labeled Cheese Pizzas. Point A is (3, 2), point

MissTica

Answer:

b and d

Step-by-step explanation:

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5 0

3 years ago

Read 3 more answers

Find the product of all real values of r for which 1/2x=r-x/7

Dahasolnce [82]

Answer:

$r = \±\sqrt{14$

$Product = -14$

Step-by-step explanation:

Given

$\frac{1}{2x} = \frac{r - x}{7}$

Required

Find all product of real values that satisfy the equation

$\frac{1}{2x} = \frac{r - x}{7}$

Cross multiply:

$2x(r - x) = 7 * 1$

$2xr - 2x^2 = 7$

Subtract 7 from both sides

$2xr - 2x^2 -7= 7 -7$

$2xr - 2x^2 -7= 0$

Reorder

$- 2x^2+ 2xr -7= 0$

Multiply through by -1

$2x^2 - 2xr +7= 0$

The above represents a quadratic equation and as such could take either of the following conditions.

(1) No real roots:

This possibility does not apply in this case as such, would not be considered.

(2) One real root

This is true if

$b^2 - 4ac = 0$

For a quadratic equation

$ax^2 + bx + c = 0$

By comparison with $2x^2 - 2xr +7= 0$

$a = 2$

$b = -2r$

$c =7$

Substitute these values in $b^2 - 4ac = 0$

$(-2r)^2 - 4 * 2 * 7 = 0$

$4r^2 - 56 = 0$

Add 56 to both sides

$4r^2 - 56 + 56= 0 + 56$

$4r^2 = 56$

Divide through by 4

$r^2 = 14$

Take square roots

$\sqrt{r^2} = \±\sqrt{14$

$r = \±\sqrt{14$

Hence, the possible values of r are:

$\sqrt{14$ or $-\sqrt{14$

and the product is:

$Product = \sqrt{14} * -\sqrt{14}$

$Product = -14$

8 0

3 years ago