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Yuri [45]
3 years ago
6

Ooooooo a bonus!!!!!!!!!!!

Mathematics
2 answers:
Katena32 [7]3 years ago
7 0

Answer:

The answer is B:25

Step-by-step explanation:

60 into two classes.

2/3= 40/60,so one class made 40 cookies and the other needs to make 20 cookies. 20 x 1 1/4 = 100/4 = 25.

so the second class needs 25 tablespoons of M&Ms for the cookies.

Plz make me brainliest :)

Ivan3 years ago
5 0

Oooooooo yes indeed HEHEHEHEHEHEHEHE

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What is 2/3 by 4/5 in fraction
kondaur [170]

Answer: If you mean to multiply, the answer is 8/15.

Step-by-step explanation:

Multiply numerator by numerator and denominator by denominator.

2 x 4 = 8

3 x 5 = 15

ANSWER: 8/15

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2 years ago
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A magazine rack contains 5 sports magazines, 7 news magazines, and 10 fashion magazines. After a magazine is chosen, it is not r
LekaFEV [45]
2/22 to simplify 1/11 not sure though but I think that’s the answer u can double check though
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3 years ago
find the values of the six trigonometric functions for angle theta in standard position if a point with the coordinates (1, -8)
frutty [35]

Answer:

cosФ = \frac{1}{\sqrt{65}} , sinФ = -\frac{8}{\sqrt{65}} , tanФ = -8, secФ = \sqrt{65} , cscФ = -\frac{\sqrt{65}}{8} , cotФ = -\frac{1}{8}

Step-by-step explanation:

If a point (x, y) lies on the terminal side of angle Ф in standard position, then the six trigonometry functions are:

  1. cosФ = \frac{x}{r}
  2. sinФ = \frac{y}{r}
  3. tanФ = \frac{y}{x}
  4. secФ = \frac{r}{x}
  5. cscФ = \frac{r}{y}
  6. cotФ = \frac{x}{y}
  • Where r = \sqrt{x^{2}+y^{2} } (the length of the terminal side from the origin to point (x, y)
  • You should find the quadrant of (x, y) to adjust the sign of each function

∵ Point (1, -8) lies on the terminal side of angle Ф in standard position

∵ x is positive and y is negative

→ That means the point lies on the 4th quadrant

∴ Angle Ф is on the 4th quadrant

∵ In the 4th quadrant cosФ and secФ only have positive values

∴ sinФ, secФ, tanФ, and cotФ have negative values

→ let us find r

∵ r = \sqrt{x^{2}+y^{2} }

∵ x = 1 and y = -8

∴ r = \sqrt{x} \sqrt{(1)^{2}+(-8)^{2}}=\sqrt{1+64}=\sqrt{65}

→ Use the rules above to find the six trigonometric functions of Ф

∵ cosФ = \frac{x}{r}

∴ cosФ = \frac{1}{\sqrt{65}}

∵ sinФ = \frac{y}{r}

∴ sinФ = -\frac{8}{\sqrt{65}}

∵ tanФ = \frac{y}{x}

∴ tanФ = -\frac{8}{1} = -8

∵ secФ = \frac{r}{x}

∴ secФ = \frac{\sqrt{65}}{1} = \sqrt{65}

∵ cscФ = \frac{r}{y}

∴ cscФ = -\frac{\sqrt{65}}{8}

∵ cotФ = \frac{x}{y}

∴ cotФ = -\frac{1}{8}    

8 0
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Anastasy [175]
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Alenkasestr [34]

Answer:

6 (may change if multiple number cubes are used; 2 dice = 6^2, 3=6^3, so on)

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