All categories

3 years ago

Resolver las siguientes ecuaciones de primer grado -5×-6=24

Mathematics

1 answer:

vova2212 [387]3 years ago

5 0

You would add -5+-6=-11
-11=24 you would divide 24/-11=-2.18

You might be interested in

PLEASE HELP!!!

Yuki888 [10]

Well, if it is only 2 customers, I think the answers would be all the choices that are two. Like CD, CC, DC, and DD. I really hope this help you :)

6 0

3 years ago

Read 2 more answers

Find the equivalent fractions and highlight common denominators

Zepler [3.9K]

Answer:

smh

Step-by-step explanation:

too ez is the answer is 12421418258475172583521838716523/12312313123651253612534

3 0

3 years ago

Please Help! Simple Geometry!

marta [7]

Answer:

A 32.1

Step-by-step explanation:

Given two points $(x_{1} ,y_{1} ) and (x_{2} ,y_{2})$ )

distance between to points = d = $\sqrt{(x_{2} - x_{1} )^{2} + (y_{2} - y_{1} )^{2} }$

Now B is (-4,5) and A is (2,0)

So AB = $\sqrt{(-4-2)^{2} +(5-0)^{2} } = \sqrt{36 + 25} = \sqrt{61\\} = 7.810...$

C is (4,10)

So BC = $\sqrt{(-4-4)^{2} +(5-10)^{2} } =\sqrt{64 + 25) } =\sqrt{89} =9.433...$

D is (8,7)

So CD = $\sqrt{(4-8)^{2} +(10-7)^{2} } =\sqrt{16 + 9} = \sqrt{25} = 5$

E is (4,5)

So DE = $\sqrt{(8-4)^{2} + (7-5)^{2} } = \sqrt{16 + 4} = \sqrt{20} = 4.472...$

and AE = $\sqrt{(4-2)^2 + (5-0)^2} =\sqrt{4+25} = \sqrt{29} = 5.385...$

Perimeter = 7.810 + 9.433 + 5 + 4.472 + 5.385 = 32.1

7 0

3 years ago

Tony will spend at most $27 on gifts. So far, he has spent $14. What are the possible additional amounts he will spend?

AleksandrR [38]

Answer:

27-14=c

Step-by-step explanation:

Also can you give brainliest to all of your questions bc it really hard to get brainliest and it be really nice you can choose who i dont really care but just please do it it helps a lot

7 0

3 years ago

Read 2 more answers

A circle's radius that has an initial radius of 0 cm is increasing at a constant rate of 5 cm per second.

djyliett [7]

Answer:

a) $r(t)=5t$

b) $A=\pi\cdot r^2$

c) $A=\pi\cdot (5t)^2$

d) $A=25\pi t^2$

Step-by-step explanation:

We know that the circle is increasing its radio from an initial state of r=0 cm, at a rate of 5 cm/s.

This can be expressed as:

$r(0)=0\\\\dr/dt=5\\\\r(t)=r(0)+dr/dt\cdot t=0+5t\\\\r(t)=5t$

a) Radius of the circle, r (in cm), in terms of the number of seconds, t since the circle started growing:

$r(t)=5t$

b) Area of the circle, A (in square cm), in terms of the circle's radius, r (in cm):

$A=\pi\cdot r^2$

c) Circle's area, A (in square cm), in terms of the number of seconds, t, since the circle started growing:

$A=\pi\cdot r^2\\\\A=\pi\cdot (5t)^2$

d) Expanded form for the area A:

$A=\pi\cdot (5t)^2=25\pi\cdot t^2$

3 0

3 years ago

Resolver las siguientes ecuaciones de primer grado -5×-6=24​

Resolver las siguientes ecuaciones de primer grado -5×-6=24