Answer:
Since the calculated value of Z= 0.242887 is less than Z (0.05) = 1.645 and falls in the critical region we reject the null hypothesis and conclude that there is not sufficient evidence to show that the proportion of women who would rather be poor and thin than rich and fat is greater than the proportion of men who would rather be poor and thin than rich and fat.
Step-by-step explanation:
Here
p1= proportion of women who would rather be poor and thin than rich and fat
p1= 315/500= 0.63
p2= proportion of men who would rather be poor and thin than rich and fat
p2= 220/400= 0.55
1) Formulate the hypothesis as
H0: p1>p2 against the claim Ha: p1 ≤ p2
2) Choose the significance level ∝0.05
3) The test Statistic under H0 , is
Z= p1^ - p2^ / sqrt( pc^qc^( 1/n1 + 1/n2))
pc^= an estimate of the common proportion
pc ^ = n1p1^ + n2p2^/ n1+n2
4) The critical region is Z≤ Z (0.05) = 1.645
5) Calculations
pc^ = 315+ 220/ 500+400= 535/900
pc^= 0.5944
and qc^= 1-0.5944= 0.4055
Thus
Z = 0.63-0.55/ sqrt ( 0.5944*0.4055( 1/500+ 1/400))
Z= 0.08/ sqrt (0.24108 (900/2000))
Z= 0.08/√0.10849
Z= 0.242887
Conclusion :
Since the calculated value of Z= 0.242887 is less than Z (0.05) = 1.645 and falls in the critical region we reject the null hypothesis and conclude that there is not sufficient evidence to show that the proportion of women who would rather be poor and thin than rich and fat is greater than the proportion of men who would rather be poor and thin than rich and fat.
